Question

SELECT B.CustomerID, SUM(C.UnitPrice * C.Quantity) AS "Total Value"
FROM Orders B, Order_Det C
WHERE B.OrderID = C.OrderID AND “Total Value” = (SELECT MAX(“Total Value”) FROM Order_Det)
GROUP BY B.CustomerID
ORDER BY "Total Value";

以上代码是我试过的。能够制作MULTIPLE订单的客户。因此，我希望通过多个数量购买和单价的总和来显示最有价值的客户。我遇到的问题是我无法存档谁是最有价值的客户。请指导我。 Tq

Answer 1

这里是!!

SELECT O.CustomerID, SUM(OD.Quantity*OD.UnitPrice) AS "Total Value"
FROM Orders O
INNER JOIN Order_Det OD ON O.OrderId = OD.OrderId
GROUP BY O.CustomerID
ORDER BY SUM(OD.Quantity*OD.UnitPrice)

或

SELECT O.CustomerID, SUM(OD.Quantity*OD.UnitPrice) AS "Total Value"
FROM Orders O, Order_Det OD 
WHERE O.OrderId = OD.OrderId
GROUP BY O.CustomerID
ORDER BY SUM(OD.Quantity*OD.UnitPrice)

对于大多数有价值的客户，

SELECT TOP 1 O.CustomerID
FROM Orders O 
INNER JOIN Order_Det OD ON O.OrderId = OD.OrderId
GROUP BY O.CustomerID
ORDER BY SUM(OD.Quantity*OD.UnitPrice) DESC

如何选择最高价值

1 个答案: