切长串

Question

我有一个很长的字符串，需要聪明地剪掉它。示例如下。
给出：

Very long string that is really too long to be placed on UI.

剪切以留下不长于N个字母的字符串：

Very long string that is really too...

这不应该像以下那样分开：

Very long string that is real...

有没有完整的解决方案/库？

Answer 1

我会尝试类似的东西。

public static String truncate(String line, int maxLength) {
    if(line.length() < maxLength) return line;
    int pos = line.lastIndexOf(" ", maxLength-3);
    if (pos <= 0) pos = maxLength - 3; // no spaces, so just cut anyway
    return line.substring(0, pos) + "...";
}

Answer 2

您需要使用setEllipsize (TextUtils.TruncateAt where）。找到文档here。

Answer 3

您可以使用StringTokenizer通过使用空格的单词剪切字符串，然后输出前几个单词。这个链接有一个很好的例子： http://www.mkyong.com/java/java-stringtokenizer-example/

Answer 4

您可以使用此类并调用其静态方法。此方法将防止outofbounds错误和空指针异常

public class SmartSubstring {

public static String smartSubstring(String str, int maxLength) {

    String subStr = str.substring(0);

    if (maxLength == 0) {
        return "";
    } else if (str.length() <= maxLength) {
        return str;
    } else {
        int i = maxLength;
        while (i >= 0) {
            while (str.length() < i) {
                i--;
            }
            if (str.charAt(i) == ' ') {
                subStr = str.substring(0, i);
                break;
            }
            i--;

        }
        return subStr;
    }
}

public static void main(String[] args) {
    String test = new String("Otomotopia is a very very long word that is "
            + "hard to contain in a mobile application screen");

    for (int i = 0; i < 200; i++) {
        String tester = SmartSubstring.smartSubstring(test, i);
        System.out.println(tester + tester.length());
    }
}
}