Question

我想在会话中加入一些vaues或object。如何添加这些额外信息

<bean id="tdrUserDetailsContextMapper" class="org.krams.tutorial.security.UserDetailsContextMapperImpl"/>   
    <bean id="ldapAuthProvider"  class="org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider">
        <constructor-arg value="in.holcim.net" />
        <!-- <beans:constructor-arg value="ldap://10.235.0.164:389" /> -->
        <constructor-arg value="ldap://10.234.12.33:389" />
        <!-- <property name="authoritiesMapper" ref="grantedAuthoritiesMapper" /> --> 
        <property name="userDetailsContextMapper" ref="tdrUserDetailsContextMapper"/>       
        <property name="useAuthenticationRequestCredentials" value="true" />
        <property name="convertSubErrorCodesToExceptions" value="true" /> 
    </bean>




  public UserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> authority) {

        List<GrantedAuthority> mappedAuthorities = new ArrayList<GrantedAuthority>();



            if("kamahire".equals(username)){
                mappedAuthorities.add(new GrantedAuthority(){
                    private static final long serialVersionUID = 4356967414267942910L;

                    @Override
                    public String getAuthority() {
                        //return "ROLE_KAMLESHA";
                        return "ROLE_USER";
                    } 

                });

            }else if(username.equals("saslanka")){
                mappedAuthorities.add(new GrantedAuthority(){
                    private static final long serialVersionUID = -5167156646226168080L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_KAMLESHA";
                    } 

                });


            /*if (granted.getAuthority().equalsIgnoreCase("MY USER GROUP")) {
                mappedAuthorities.add(new GrantedAuthority(){
                    private static final long serialVersionUID = 4356967414267942910L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_USER";
                    } 

                });
            } else if(granted.getAuthority().equalsIgnoreCase("MY ADMIN GROUP")) {
                mappedAuthorities.add(new GrantedAuthority() {
                    private static final long serialVersionUID = -5167156646226168080L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_ADMIN";
                    }
                });
            }*/
        }else{

                mappedAuthorities.add(new GrantedAuthority(){
                    private static final long serialVersionUID = -5167156646226168780L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_ADMIN2";
                    }

                });


            }
        System.out.println("User name is :" + username + " ROLE" + mappedAuthorities.get(0).getAuthority() );
        return new User(username, "", true, true, true, true, mappedAuthorities);
    }

    @Override
    public void mapUserToContext(UserDetails arg0, DirContextAdapter arg1) {
    }


}

我想用额外的参数在上面的类中设置session或principal对象。我该如何添加。

请帮忙。

Answer 1

您可以创建User对象的子类，然后可以通过

访问该对象

SecurityContextHolder.getContext().getAuthentication().getPrincipal()

或者您可以使用身份验证事件侦听器来进一步准备用户会话。

public class MySessionPreparator implements ApplicationListener<AuthenticationSuccessEvent> {

    @Override
    public void onApplicationEvent(AuthenticationSuccessEvent event) {
        RequestContextHolder.currentRequestAttributes().setAttribute("foo", "bar", RequestAttributes.SCOPE_SESSION);
    }

}

Spring Security 3和Web应用程序会话

1 个答案: