Question

这是我的SQL查询

select * from customer where cust_acnt_nbr IN (select cust_acnt_nbr from Asset where dstrct_id IN (select dstrct_id from dstrct where dstrct_nm = 'ATLANTA'))

我将此SQL转换为HQL

    final Query query = getCurrentSession().createQuery(
            "from customer where cust_acnt_nbr in (select cust_acnt_nbr from Asset where dstrct_id in (select dstrct_id from dstrct where dstrct_nm = :name))");
    query.setParameter("name", districtName);

这会出错：

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.hibernate.hql.internal.ast.QuerySyntaxException: customer is not mapped [from customer where cust_acnt_nbr in (select cust_acnt_nbr from com.ironmountain.model.Asset where dstrct_id in (select dstrct_id from dstrct where dstrct_nm = :name))]

Answer 1

如果你仔细看看这里：customer is not mapped，我认为很清楚。问题是Hibernate无法找到customer实体。 HQL中的Java类和属性区分大小写，customer可能是Customer。

Answer 2

我有这个问题，hibernate区分大小写。这个查询是我的查询：查询查询= session.createQuery（＆＃34;从学生e中选择e，其中e.id =：id＆＃34;）;

我改变了学生，这个查询是正确的：查询查询= session.createQuery（＆＃34;从学生e中选择e，其中e.id =：id＆＃34;）;

错误org.hibernate.hql.internal.ast.QuerySyntaxException

2 个答案: