Question

我有一个定价数组

pricing = new Array();

pricing[1] = 35;
pricing[2] = 60;
pricing[3] = 84;
pricing[4] = 104;
pricing[5] = 120;
pricing[6] = 132;
pricing[7] = 140;
pricing[8] = 144;
pricing[9] = 153;
pricing[10] = 160;

10以下的所有商品都有价格，10以上的价格都与10相同。

它只有20，所以我最初做的只是重复11 - 20的价格。但那太浪费了，我怎么能告诉我阵列一切＆gt; 10 = 160

p.s我的最终版本是精简的：）

Answer 1

您可以按原样保留数组，并使用如下函数：

var getPrice = function(arr, index){
    return arr[index > 10 ? 10 : index];
}

Answer 2

var pricing = [], i;
pricing.push(35);
pricing.push(60);
pricing.push(84);
pricing.push(104);
pricing.push(120);
pricing.push(132);
pricing.push(140);
pricing.push(144);
pricing.push(153);
for (i = 0; i < 11; i++) {
    pricing.push(160);
}

我也为此做了JSFiddle。

@CD表示push function可以将多个项目附加到数组中。代码看起来像这样：

var pricing = [], value = 160;
pricing.push(35);
pricing.push(60);
pricing.push(84);
pricing.push(104);
pricing.push(120);
pricing.push(132);
pricing.push(140);
pricing.push(144);
pricing.push(153);
pricing.push(value, value, value, value, value, value, value, value, value, value, value);

Answer 3

i=10;
while(i--) { pricing[i+10] = 160; }

Answer 4

pricing = new Array();
var arraySize = 100;

pricing[1] = 35;
pricing[2] = 60;
pricing[3] = 84;
pricing[4] = 104;
pricing[5] = 120;
pricing[6] = 132;
pricing[7] = 140;
pricing[8] = 144;
pricing[9] = 153;

for(var x = 10; x < arraySize; x++)
    pricing[x] = 160

console.log(pricing);

Answer 5

您错过了数组中的第一个条目（因为它基于0）。我会改变它：

pricing = new Array(20);

pricing[0] = 35;
pricing[1] = 60;
pricing[2] = 84;
pricing[3] = 104;
pricing[4] = 120;
pricing[5] = 132;
pricing[6] = 140;
pricing[7] = 144;
pricing[8] = 153;
pricing[9] = 160;

然后你可以用这个来设置最后10个：

for(var x = 10; x < pricing.length; x++) {
    pricing[x] = pricing[9];
}

Example fiddle。

jQuery Number数组，超过一定数量的所有内容

5 个答案: