Question

我有两个NSMutableArrays。每个都包含一个自定义单词对象。自定义单词有2个属性文本和频率。现在我想以这样的方式组合这两个arrays，如果这两个数组中有相同的文本，那么它应该比较这两个文本的频率并选择两者中的最高频率。而且它应该删除array中的重复项。我为此尝试了所有逻辑，但无法做到这一点。任何人都可以帮助我解决这个问题。遵循代码。但它也应删除重复项。

for (int i = 0; i < [array count]; i++) {
  for (int j = 0; j < [array count]; j++)  {
    if ([[[array objectAtIndex:i]firstWord] isEqualToString:[[array objectAtIndex:j] firstWord]]) {

      if ([[array objectAtIndex:i] frequency] < [[array objectAtIndex:j] frequency]) {
        CustomWordFrequency *word = [array objectAtIndex:i];
        word.frequency = [[array objectAtIndex:j] frequency];
        [array replaceObjectAtIndex:i withObject:word];
      }

    }
  }
}

Answer 1

合并两个阵列。
按文本ASC，频率DESC

循环通过阵列
一个。查看数组中的下一个项目。如果文本与当前单词相同，请将其从数组中删除。如果不同，请继续循环。

NSArray *combined = [firstArray arrayByAddingObjectsFromArray:secondArray];
[combined sortUsingComparator:^(id firstObject, id secondObject) {
  NSComparisonResult *result = [firstObject.text compare:secondObject.text];
  if (result == NSOrderedAscending) return NSOrderedAscending;
  if (result == NSOrderedDescending) return NSOrderedDescending;
  if (result == NSOrderedSame) {
    result = [firstObject.frequency compare:secondObject.frequency];
    if (result == NSOrderedAscending) return NSOrderedDescending;
    if (result == NSOrderedDescending) return NSOrderedAscending;
    if (result == NSOrderedSame) return NSOrderedSame;
  }
}];
for (int i = 0; i < [combined count] - 2; ++i) {
   CustomWordFrequency *word = [combined objectAtIndex:i];
   int j = i + 1;
   while ([word.text compare:[combined objectAtIndex:j].text == NSOrderedSame) {
     [combined removeObjectAtIndex:j];
     j++;
     if (j == [combined count]) {break;}
   }
   if (i >= [combined count] - 2) {break;} // the count keeps changing so check here
}

Answer 2

NSMutableArray *combinedArray = [[NSMutableArray alloc] init];
BOOL flagForMatchFound = FALSE;
for(CustomWordFrequency *firstWord in firstArray)
 {
   flagForMatchFound = FALSE;
   for(CustomWordFrequency *secondWord in secondArray)
   {
       if([firstWord.firstWord isEqualToString:secondWord.firstWord])
       {
          if(firstWord.frequency >= secondWord.frequency)
          {
               [combinedArray addObject:firstWord];
               flagForMatchFound = TRUE;
          }
          else
               [combinedArray addObject:secondWord];
       }
       else
       {
          if(!flagForMatchFound)
              [combinedArray addObject:secondWord]; 
       }
   }
 }

从自定义对象的NSArray中删除重复项也会比较和编辑它们

2 个答案: