Question

在我的应用程序中我从服务器获得J SON格式的响应。在解析时，它在响应中显示未终止的错误。因此无法解析它。

我的json编码

 HttpClient client = new DefaultHttpClient();
        HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000);
        HttpConnectionParams.setSoTimeout(client.getParams(), 10000);

        HttpResponse response;

        try {

            HttpPost post = new HttpPost(getString(R.string.base_url)+ "login?json=");

            Time dtNow = new Time();
            dtNow.setToNow();
            String last_login_ts = dtNow.format("%Y-%m-%d %H:%M:%S");

            // Log.v("Login_ts",""+last_login_ts);

            json.put("pmailtxt", "" + et_username.getText().toString());
            json.put("loginpasstxt", "" + et_password.getText().toString());
            json.put("merchant_code", "" + getString(R.string.merchant_code));
            json.put("last_login_ts", "" + last_login_ts);

            // Log.v("Login", ""+json);

            // Toast.makeText(getApplicationContext(), ""+json, 700).show();

            post.setHeader("json", json.toString());
            StringEntity se = new StringEntity(json.toString());

            se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json"));
            post.setEntity(se);
            response = client.execute(post);

            // Checking response
            if (response != null) {

                // get a data
                InputStream in = response.getEntity().getContent();
                String a = json_res_class.convertStreamToString(in);
                Log.v("Response", ""+a);//here am getting response

此处我的回复错误

06-07 16:05:55.132: W/System.err(930): org.json.JSONException: Unterminated array at  character 5 of [  {"loginSuccess":0,"message":"Wrong username or password"}]

我如何纠正这个问题，任何人都知道请帮助我解决这个问题。

Answer 1

异常消息很明显...... JSON的最后一个字符缺失，因此您的数组未关闭。因为它没有关闭，所以无法解析。

此外，在解析的情况下，您应该捕获异常。

Answer 2

查看以下代码

try {
            HttpResponse response = httpclient.execute(httppost);

            int responsecode = response.getStatusLine().getStatusCode();
            if (responsecode == 200) {

                InputStream in = response.getEntity().getContent();
                resultstring = Util.convertinputStreamToString(in);
            } 

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

检查你的convertinputStreamToString函数一次。

public static String convertinputStreamToString(InputStream ists)
        throws IOException {
    if (ists != null) {
        StringBuilder sb = new StringBuilder();
        String line;

        try {
            BufferedReader r1 = new BufferedReader(new InputStreamReader(
                    ists, "UTF-8"));
            while ((line = r1.readLine()) != null) {
                sb.append(line).append("\n");
            }
        } finally {
            ists.close();
        }
        return sb.toString();
    } else {
        return "";
    }
}

响应中的JSON异常无终止错误？

2 个答案: