Question

在我的Android App中解析此JSON数据时遇到问题：

[{"personid":20,"personName":"Ross Gallagher update3","email":"ross_gallagher@rossgallagher.co.uk","birthday":{"date":"2013-01-01 00:00:00","timezone_type":3,"timezone":"America\/Los_Angeles"},"anniversary":{"date":"1900-01-01 00:00:00","timezone_type":3,"timezone":"America\/Los_Angeles"},"Credit":2}]

我得到的错误是：

W/System.err: org.json.JSONException: Value [{"birthday":{"date":"2013-01-01 00:00:00","timezone":"America\/Los_Angeles","timezone_type":3},"anniversary":{"date":"1900-01-01 00:00:00","timezone":"America\/Los_Angeles","timezone_type":3},"email":"ross_gallagher@rossgallagher.co.uk","personName":"Ross Gallagher update8","Credit":2,"personid":20}] of type org.json.JSONArray cannot be converted to JSONObject

我的JSON解析器代码是：

public JSONObject getJSONFromUrl(String url)
{
    HttpEntity httpEntity = null;
    JSONObject respObject = null;

    // Making HTTP request
    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpGet httpGet = new HttpGet(url);

        HttpResponse httpResponse = httpClient.execute(httpGet);
        httpEntity = httpResponse.getEntity();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    if(httpEntity != null){
        try {
            respObject = new JSONObject(EntityUtils.toString(httpEntity));
        } catch (JSONException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        //....
    }
    // return JSON
    return respObject;
}

我只需要从这个JSON对象中提取生日详细信息以及姓名，电子邮件，信用和周年纪念日。

任何建议都将不胜感激！

Answer 1

更改

respObject = new JSONObject(EntityUtils.toString(httpEntity));

到

respObject = new JSONArray(EntityUtils.toString(httpEntity));

ofcourse respObject必须是JSONArray

Answer 2

问题在于您的JSON字符串。您需要移除方形支架 [] 。方形支架用于引用数组元素。 JSON解析器将尝试将其转换为数组对象，因为json数据位于square braket内。

如果对你有帮助，请接受我的回答。

Answer 3

因为你试图解析的对象实际上是一个JSONArray而不是JSONObject ..所以你从那个JSONArray获得JSONObject

JSONArray jsonArray = new JSONArray（EntityUtils.toString（httpEntity））;

JSONOject jsonObject = jsonArray.getJSONObject（0）;

从这个jsonObject你会得到生日详情...

Android JSON解析错误与日期

3 个答案: