Question

我使用以下代码输出显示的xml中的所有节点。

        $cursor = "?cursor=-1"
        $xml= new SimpleXmlElement($to->OAuthRequest('http://twitter.com/statuses/followers.xml?$cursor'));
        foreach ($xml->xpath('/users_list/users/user') as $user) {
            $id = $user->id;
            $names .= $user->screen_name;
            $profimg = $user->profile_image_url;
        }
        $next = $user->next_link;
        $prev = $user->prev_link;
        $pusharray = array("$names", "$next", "$prev");

我回来的只有Array ( [0] => [1] => [2] => )

下载xml的样本
http://twitter.com/statuses/followers/barakobama.xml?cursor=-1

我做错了什么？每个人都建议的一切都没有奏效！我疯了。

Answer 1

您需要：

$id = $user['id'];

或

$id = $user->attributes()->id;

见basic usage of SimpleXML。你正在做的不是查询属性的有效方法。

Answer 2

$users_list = simplexml_load_file('http://twitter.com/statuses/followers/barakobama.xml?cursor=-1');

foreach ($users_list->users->user as $user)
{
    echo $user->id, ' ', $user->screen_name, ' ', $user->profile_image_url, "<br />\n";
}

echo 'prev: ', $users_list->previous_cursor, ' - next: ', $users_list->next_cursor;

该XML中没有next_link或prev_link，我假设您在谈论previous_cursor和next_cursor

simplexml + foreach + twitter带有意想不到的结果

2 个答案: