SELECT distinct fp.fcast_product_id, fp.id, fp.customer_id, pm.product_name FROM
f_product AS fp LEFT JOIN product_master AS pm ON fp.customer_id=pm.customer_id
WHERE fp.customer_id = '10004'
我得到了这个答案
710070 934 10004 EUREKA
710070 934 10004 EXCELLAY
711080 2933 10004 EUREKA
711080 2933 10004 EXCELLAY
但我想要这样
710070 934 10004 EUREKA
711080 2933 10004 EXCELLAY
示例表结构
表1:f_product
id fcast_product_id customer_id
14 710010 24018
15 710010 24018
79 711080 28006
80 711080 39963
81 711080 39963
82 711080 10004
594 710020 12238
595 710020 12238
596 710020 14004
597 710020 14004
598 710020 30112
599 710020 30112
600 710020 39043
601 710020 40173
934 710070 10004
表2:product_master
id product_id customer_id product_name
24 710010 10082 test8
25 711020 11006 test9
26 711020 11006 test9
27 710010 11026 test8
28 710010 11029 test8
29 711020 11029 test9
35 710070 10004 EUREKA
36 711080 10004 EXCELLAY
53 710070 12242 EUREKA
59 710070 12347 EUREKA
80 710070 19023 EUREKA
21 711080 10077 EXCELLAY
33 711080 11030 EXCELLAY
62 711080 14037 EXCELLAY
答案 0 :(得分:0)
你确定要分明吗?
试试这个:
SELECT fp.fcast_product_id, fp.id, fp.customer_id, pm.product_name
FROM
f_product AS fp
LEFT JOIN product_master AS pm
ON fp.customer_id=pm.customer_id
and pm.product_id =fcast_product_id
WHERE fp.customer_id = '10004'
B.t.w。你的例子中没有id 2933