我正在使用C ++和MySQL C API(版本5.1.31 ubuntu2)编写程序。但是,如果查询是 UPDATE ,那么在执行“RowsReturned = mysql_num_rows(Result);”行时会出现 Segmentation Fault 错误。
//this code snippet contains only the relevant code
MYSQL_RES *Result;
long RowsReturned;
MYSQL_RES *MYSQLDB::RunQuery( const char* Query )
{
if( mysql_query( Connection, Query) )
{
std::cout << "Error: " << mysql_error( Connection );
exit(1);
}
Result = mysql_store_result( Connection );
RowsReturned = mysql_num_rows( Result );
return Result;
}
使用g ++ 4.3.3编译(g ++ test.cpp -I / usr / include / mysql -L / usr / lib / mysql -lmysqlclient_r -o Test)
提前致谢。
//this snippet contains the entire class code
class MYSQLDB
{
public:
void Connect( const char* DB );
MYSQL_RES *RunQuery( const char* Query );
long NumRows();
void Close();
MYSQL_ROW GetRow();
private:
MYSQL *Connection;
MYSQL_RES *Result;
MYSQL_ROW Row;
long RowsReturned;
};
void MYSQLDB::Connect( const char* DB )
{
Connection = mysql_init( NULL );
if( Connection == NULL )
{
std::cout << "Error: " << mysql_error( Connection );
exit( 1 );
}
if ( mysql_real_connect( Connection, "localhost", "root", "password", DB, 0, NULL, 0 ) == NULL)
{
std::cout << "Error: " << mysql_error( Connection );
exit(1);
}
}
MYSQL_RES *MYSQLDB::RunQuery( const char* Query )
{
if( mysql_query( Connection, Query) )
{
std::cout << "Error: " << mysql_error( Connection );
exit(1);
}
Result = mysql_store_result( Connection );
RowsReturned = (long)mysql_num_rows( Result ); //ERROR!!!!!!!
return Result;
}
long MYSQLDB::NumRows()
{
return RowsReturned;
}
void MYSQLDB::Close()
{
mysql_free_result( Result );
mysql_close( Connection );
}
MYSQL_ROW MYSQLDB::GetRow()
{
return mysql_fetch_row( Result );
}
答案 0 :(得分:3)
来自mysql文档:
如果语句没有返回结果集,则mysp_store_result()返回空指针(例如,如果它是INSERT语句)。您正在更新,因此您的结果为NULL。
尝试这样的事情:
Result = mysql_store_result( Connection );
if (Result) {
RowsReturned = mysql_num_rows( Result );
} else {
RowsReturned = 0;
}