Question

这是我的代码

for(id tempLangItem in jp.staffData)
        {
 NSMutableDictionary *temp=[[NSMutableDictionary alloc] initWithDictionary:tempLangItem];
            NSString *name = [temp objectForKey:@"lang_name"];
            NSLog(@"item_name =%@",name);
            NSLog(@"value in dictionary=%@",temp);



}

这些是日志详情

item_name =marinieres

 value_in_dictionary={
    "lang_id" = 2;
    "lang_name" = "\U7a46\U840a\U65afmarinieres";
    time = "2013-06-05 05:14:50";
}

为什么lang_name=\U7a46\U840a\U65afmarinieres日志在value_in_dictionary日志中显示正确时，为item_name提供{{1}}。

Answer 1

尝试

NSMutableDictionary *temp=[[NSMutableDictionary alloc]init];
[temp setObject:@"marinieres" forKey:@"lang_name"];

NSString *name = [temp objectForKey:@"lang_name"];
NSLog(@"item_name =%@",name);
NSLog(@"value in dictionary=%@",temp);

以及我的日志显示

2013-06-06 12:38:02.337 Cool[96423:11303] item_name =marinieres
2013-06-06 12:38:04.022 Cool[96423:11303] value in dictionary={
    "lang_name" = marinieres;
}

1快速问题：如果是NSDictionary，为什么要创建新实例？

 NSMutableDictionary *temp=[[NSMutableDictionary alloc] initWithDictionary:tempLangItem];

尝试使用tempLangItem

字典给出不正确的价值

1 个答案: