Question

我创建了一个查询，在c＃中一次插入两个ms访问表。我得到了例外

{System.Data.OleDb.OleDbException：在SQL结束后找到的字符声明。在 System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling（OleDbHResult hr）at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult（tagDBPARAMS dbParams，Object＆amp; executeResult）at System.Data.OleDb.OleDbCommand.ExecuteCommandText（对象＆安培; executeResult）at System.Data.OleDb.OleDbCommand.ExecuteCommand（的CommandBehavior 行为，对象＆amp; executeResult）at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal（的CommandBehavior 行为，String方法）at System.Data.OleDb.OleDbCommand.ExecuteNonQuery（）at CompanyDetails.Model.CompanyDetailsModel.setCompanyDetailsToDB（CompanyDetailsDataList _cmpDetailsList中的E：\ Project \ PBAttendence \ ModifyPrivileage \ CompanyDetails \ Model \ CompanyDetailsModel.cs：line 62}

我的示例代码如下，请解决我的问题。抱歉我的英语不好。

int companyID = _cmpDetailsList[0].CompanyID;
                    string companyName = _cmpDetailsList[0].CompanyName;
                    string contactID = _cmpDetailsList[0].ContactID;
                    string companyAddress = _cmpDetailsList[0].CompanyAddress;

                    if (companyID == -1)
                    {
                        OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity;" + "); ", conn);
                        conn.Open();
                        cmd.ExecuteNonQuery();
                        conn.Close();
                    }
                    else
                    {
                        OleDbCommand upcmd = new OleDbCommand("update CompanyDetails set [CompanyName] = '" + companyName + "',[CompanyAddress] = '" + companyAddress + "',[ContactID] = '" + contactID + "' where [CompanyID] = @cmpID;", conn);
                        conn.Open();
                        upcmd.Parameters.AddWithValue("@cmpID", companyID);
                        upcmd.ExecuteNonQuery();
                        conn.Close();
                    }

现在我分成两个插入命令但是我收到了错误{System.Data.OleDb.OleDbException：语法错误。在查询表达式'从UserDetails中选择[UserID];

OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');", conn);
                        conn.Open();
                        cmd.ExecuteNonQuery();
                        conn.Close();
                        OleDbCommand cmd1 = new OleDbCommand("Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity" + ");", conn);
                        conn.Open();
                        cmd1.ExecuteNonQuery();
                        conn.Close();

Answer 1

问题在于这行代码：

OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity;" + "); ", conn);

您在同一个insert中有两个OleDbCommand语句。尝试将其分为两个不同的步骤：

插入公司详细信息表
插入UserCompanyDetails表

希望这有助于你

Answer 2

你不能拥有;在Access中的查询中。请参阅http://office.microsoft.com/en-us/access-help/HV080760224.aspx您必须按照@juanreyesv

的建议单独执行两个插入

您必须执行3次查询，

使用您的sql执行插入："Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "')
使用获取@@身份 Select @@identity并将其存储在变量idnt
使用2.中获得的标识值进行第三次插入： "Insert into UserCompanyDetails([UserID],[CompanyID]) Select UserID, " + idnt.ToString() + " from UserDetails"

请参阅http://msdn.microsoft.com/en-us/library/ks9f57t0%28VS.71%29.aspx

Answer 3

首先，使用raw sql命令然后生成sql的代码会更容易你可能会考虑制作一个存储过程，因为你的命令变得有点复杂了如果我是对的，你现在要做的是：

Insert into table1(x,y,z) values a,b,c;
Insert into table2(x,y) values select * from table3; , @@identity

第二个sql命令在语法和逻辑上都是无效的，因为您在命令期间插入新记录，所以@@ identity不会是静态的。
我的建议是做这样的事情：

Insert into table1(x,y,z) values a,b,c;
declare @table1Id int = @@identity
Insert into table2(x,y) select colA, @table1Id from table3;

执行ms-access查询时出错

3 个答案: