来自url的简单django传递参数

Question

我习惯使用网址在django中传递参数，我有以下网址：

mywebsite/view-negotiation/?negotiation=7

我期待以下规则能够抓住它：

url(r'view-negotiation/(?P<negotiation>\d+)', 'myview.views.myview')

但我发现404页面找不到错误。我在这里做错了什么？

Answer 1

@karthikr给出url模式可以与你的网址匹配

 url(r'^view-negotiation/(?P<negotiation>\d+)/$', 'myview.views.myview')

并尝试此操作以从您的视图中访问参数

 def myview(request, negotiation):
     #negotiation is the parameter catch form url 
     #i.e nagotiation is a variable that having 7 or any other intiger passed by url
     #other stuff goes here