我有一个包含超过1500个json对象的文件,我想在R中使用。我已经能够将数据作为列表导入,但是很难将其强制转换为有用的结构。我想创建一个数据框,其中包含每个json对象的行和每个key:value对的列。
我用这个小的假数据集重新创建了我的情况:
[{"name":"Doe, John","group":"Red","age (y)":24,"height (cm)":182,"wieght (kg)":74.8,"score":null},
{"name":"Doe, Jane","group":"Green","age (y)":30,"height (cm)":170,"wieght (kg)":70.1,"score":500},
{"name":"Smith, Joan","group":"Yellow","age (y)":41,"height (cm)":169,"wieght (kg)":60,"score":null},
{"name":"Brown, Sam","group":"Green","age (y)":22,"height (cm)":183,"wieght (kg)":75,"score":865},
{"name":"Jones, Larry","group":"Green","age (y)":31,"height (cm)":178,"wieght (kg)":83.9,"score":221},
{"name":"Murray, Seth","group":"Red","age (y)":35,"height (cm)":172,"wieght (kg)":76.2,"score":413},
{"name":"Doe, Jane","group":"Yellow","age (y)":22,"height (cm)":164,"wieght (kg)":68,"score":902}]
数据的一些功能:
基于这个问题:R list(structure(list())) to data frame,我尝试了以下内容:
json_file <- "test.json"
json_data <- fromJSON(json_file)
asFrame <- do.call("rbind.fill", lapply(json_data, as.data.frame))
使用我的真实数据和这些假数据,最后一行给出了这个错误:
Error in data.frame(name = "Doe, John", group = "Red", `age (y)` = 24, :
arguments imply differing number of rows: 1, 0
答案 0 :(得分:52)
你只需要用NAs替换你的NULL:
require(RJSONIO)
json_file <- '[{"name":"Doe, John","group":"Red","age (y)":24,"height (cm)":182,"wieght (kg)":74.8,"score":null},
{"name":"Doe, Jane","group":"Green","age (y)":30,"height (cm)":170,"wieght (kg)":70.1,"score":500},
{"name":"Smith, Joan","group":"Yellow","age (y)":41,"height (cm)":169,"wieght (kg)":60,"score":null},
{"name":"Brown, Sam","group":"Green","age (y)":22,"height (cm)":183,"wieght (kg)":75,"score":865},
{"name":"Jones, Larry","group":"Green","age (y)":31,"height (cm)":178,"wieght (kg)":83.9,"score":221},
{"name":"Murray, Seth","group":"Red","age (y)":35,"height (cm)":172,"wieght (kg)":76.2,"score":413},
{"name":"Doe, Jane","group":"Yellow","age (y)":22,"height (cm)":164,"wieght (kg)":68,"score":902}]'
json_file <- fromJSON(json_file)
json_file <- lapply(json_file, function(x) {
x[sapply(x, is.null)] <- NA
unlist(x)
})
每个元素都有一个非空值后,您可以调用rbind
而不会收到错误:
do.call("rbind", json_file)
name group age (y) height (cm) wieght (kg) score
[1,] "Doe, John" "Red" "24" "182" "74.8" NA
[2,] "Doe, Jane" "Green" "30" "170" "70.1" "500"
[3,] "Smith, Joan" "Yellow" "41" "169" "60" NA
[4,] "Brown, Sam" "Green" "22" "183" "75" "865"
[5,] "Jones, Larry" "Green" "31" "178" "83.9" "221"
[6,] "Murray, Seth" "Red" "35" "172" "76.2" "413"
[7,] "Doe, Jane" "Yellow" "22" "164" "68" "902"
答案 1 :(得分:25)
如果您使用library(jsonlite)
和函数fromJSON
,这非常简单。它还处理null
值并将其转换为NA
。
json_file <- '[{"name":"Doe, John","group":"Red","age (y)":24,"height (cm)":182,"wieght (kg)":74.8,"score":null},
{"name":"Doe, Jane","group":"Green","age (y)":30,"height (cm)":170,"wieght (kg)":70.1,"score":500},
{"name":"Smith, Joan","group":"Yellow","age (y)":41,"height (cm)":169,"wieght (kg)":60,"score":null},
{"name":"Brown, Sam","group":"Green","age (y)":22,"height (cm)":183,"wieght (kg)":75,"score":865},
{"name":"Jones, Larry","group":"Green","age (y)":31,"height (cm)":178,"wieght (kg)":83.9,"score":221},
{"name":"Murray, Seth","group":"Red","age (y)":35,"height (cm)":172,"wieght (kg)":76.2,"score":413},
{"name":"Doe, Jane","group":"Yellow","age (y)":22,"height (cm)":164,"wieght (kg)":68,"score":902}]'
library(jsonlite)
fromJSON(json_file)
# name group age (y) height (cm) wieght (kg) score
# 1 Doe, John Red 24 182 74.8 NA
# 2 Doe, Jane Green 30 170 70.1 500
# 3 Smith, Joan Yellow 41 169 60.0 NA
# 4 Brown, Sam Green 22 183 75.0 865
# 5 Jones, Larry Green 31 178 83.9 221
# 6 Murray, Seth Red 35 172 76.2 413
# 7 Doe, Jane Yellow 22 164 68.0 902
str(fromJSON(json_file))
# 'data.frame': 7 obs. of 6 variables:
# $ name : chr "Doe, John" "Doe, Jane" "Smith, Joan" "Brown, Sam" ...
# $ group : chr "Red" "Green" "Yellow" "Green" ...
# $ age (y) : int 24 30 41 22 31 35 22
# $ height (cm): int 182 170 169 183 178 172 164
# $ wieght (kg): num 74.8 70.1 60 75 83.9 76.2 68
# $ score : int NA 500 NA 865 221 413 902
答案 2 :(得分:2)
要删除空值,请使用参数nullValue
json_data <- fromJSON(json_file, nullValue = NA)
asFrame <- do.call("rbind.fill", lapply(json_data, as.data.frame))
这样输出中就不会有任何不必要的引号
答案 3 :(得分:2)
library(rjson)
Lines <- readLines("yelp_academic_dataset_business.json")
business <- as.data.frame(t(sapply(Lines, fromJSON)))
您可以尝试将JSON数据加载到R
中答案 4 :(得分:0)
dplyr::bind_rows(fromJSON(file_name))