Question

Create table #Tbl
(
ID int not null,
Keyword nvarchar(max)
)
Insert into #Tbl Values ('0','Cryptography')
Insert into #Tbl Values ('1','Cryptography')
Insert into #Tbl Values ('4','Cryptography')
Insert into #Tbl Values ('0','SQL')
Insert into #Tbl Values ('0','SQL')
Insert into #Tbl Values ('3','Cloud Computing')
Insert into #Tbl Values ('6','Recursion')
Insert into #Tbl Values ('8','Recursion')
Insert into #Tbl Values ('0','Universe')
Insert into #Tbl Values ('0','Universe')
Insert into #Tbl Values ('7','Universe')

我需要获得具有多个ID的标题，并且至少有一个ID为零。

所以预期结果将是：

Cryptography
Universe

我尝试过以下查询，但无法添加“至少一个id为零”条件

select Keyword,COUNT(distinct id) from #Tbl
group by Keyword
having COUNT(distinct id)>1

我该怎么办？谢谢你的帮助。

Answer 1

假设您的ID从0开始，以下内容应该可以正常工作

select Keyword,COUNT(distinct id) from #Tbl
group by Keyword
having COUNT(distinct id)>1 and MIN(id) = 0

Answer 2

有很多方法可以做到这一点，例如：

SELECT DISTINCT Keyword
FROM #Tbl T
WHERE EXISTS (SELECT 1 FROM #Tbl WHERE Keyword = T.Keyword
              AND ID = 0)
AND EXISTS (SELECT 1 FROM #Tbl WHERE Keyword = T.Keyword
              AND ID != 0)

带有演示的

Here is a sqlfiddle。

Answer 3

这应该这样做：

SELECT Keyword
FROM  #Tbl
WHERE Keyword IN (SELECT DISTINCT Keyword FROM #Tbl WHERE ID = 0)
GROUP BY Keyword
HAVING COUNT(DISTINCT id) > 1

Answer 4

这是另一种方法：

SELECT Keyword, COUNT(DISTINCT ID)
FROM #Tbl
GROUP BY Keyword
HAVING COUNT(DISTINCT ID) > ALL (SELECT COUNT(DISTINCT NULLIF(ID, 0)) UNION ALL SELECT 1)
;

获取具有多个值的记录，并且其中至少有一个值为零

4 个答案: