无法使用gmongo在mongo中插入文档

时间:2013-06-05 15:17:23

标签: grails groovy gmongo

我有以下代码在groovy中插入文档,但我在grails应用程序中不断收到此错误

   def zipcode = getDocumentCollection()
   zipcode.insert(["city": "ACMAR", "loc": [-86.51557F, 33.584132F], "pop": 6055, "state": "AL", "_id": "35004"])
  

没有方法签名:com.mongodb.DBApiLayer $ MyCollection.insert()   适用于参数类型:(java.util.LinkedHashMap)值:   [[城市:ACMAR,loc:[ - 86.51557,33.584133],...]]可能的解决方案:   insert([Lcom.mongodb.DBObject;),insert(java.util.List),   insert([Lcom.mongodb.DBObject;,com.mongodb.WriteConcern),   insert(com.mongodb.DBObject,com.mongodb.WriteConcern),   insert(com.mongodb.WriteConcern,[Lcom.mongodb.DBObject;),   insert(java.util.List,com.mongodb.WriteConcern)

此代码取自gmongo的示例。我为什么会收到错误的任何想法?

更新
尝试@ dmahapatro的方法后,我在Grails应用程序中收到以下错误:

2013-06-06 09:54:21,493 [localhost-startStop-1] ERROR context.GrailsContextLoader  - Error initializing the application: Error creating bean with name 'org.springframework.data.mongodb.monitor.OperationCounters#0': Unsatisfied dependency expressed through constructor argument with index 0 of type [com.mongodb.Mongo]: Could not convert constructor argument value of type [com.gmongo.GMongo] to required type [com.mongodb.Mongo]: Failed to convert value of type 'com.gmongo.GMongo' to required type 'com.mongodb.Mongo'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [com.gmongo.GMongo] to required type [com.mongodb.Mongo]: no matching editors or conversion strategy found
org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'org.springframework.data.mongodb.monitor.OperationCounters#0': Unsatisfied dependency expressed
 through constructor argument with index 0 of type [com.mongodb.Mongo]: Could not convert constructor argument value of type [com.gmongo.GMongo] to required type [com.mongodb.Mongo]: Failed to
 convert value of type 'com.gmongo.GMongo' to required type 'com.mongodb.Mongo'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [com.gmongo.GMongo] to required type [com.mongodb.Mongo]: no matching editors or conversion strategy found
        at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:334)
        at java.util.concurrent.FutureTask.run(FutureTask.java:166)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1110)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:603)
        at java.lang.Thread.run(Thread.java:722)

1 个答案:

答案 0 :(得分:0)

当你使用insert时,你需要提供名为args的键值对(我想你也可以使用一个地图,但它会更简洁)。

zipcode.insert(city: "ACMAR", loc: [-86.51557F, 33.584132F], pop: 6055, state: "AL", _id: "35004")

如果您想使用HashMap,请使用左移运算符将文档插入集合中。

zipcode << ["city": "ACMAR", "loc": [-86.51557F, 33.584132F], "pop": 6055, "state": "AL", "_id": "35004"]

如果我使用聚合,我会采用第二种方法。

<强>示例

这对我来说非常适合测试。

@Grab(group='com.gmongo', module='gmongo', version='1.0')
import com.gmongo.GMongo

def mongo = new GMongo("127.0.0.1", 27017)
def db = mongo.getDB("gmongo")
//Instead of doing below I can also use db.zipcodes.insert(blah: blah)
def zipCode = db.getCollection("zipcodes")
zipCode.insert(city: "ACMAR", loc: [-86.51557F, 33.584132F], pop: 6055, state: "AL", _id: "35004")
zipCode << [city: "DUMMY", loc: [-86.51587F, 33.584172F], pop: 6056, state: "AL", _id: "35005"]

assert db.zipcodes.findOne(city: "DUMMY").city == 'DUMMY'
assert db.zipcodes.findOne(city: "ACMAR").city == 'ACMAR'