<?php
session_start();
include "config.php";
if(isset($_POST['sub'])) {
if(!empty($_POST["column"])) {
$a = $_POST['column']; // column name
} else {
$a ="";
echo "please click on the right input";
}
$r="select '".$a."' , count(*) as '".$a."' from emc_leadgen group by '".$a."' ";
$t=mysql_query($r);
if (!$t)
{
$message = 'ERROR:' . mysql_error();
return $message;
}
else
{
$i = 0;
?>
<html xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns="http://www.w3.org/TR/REC-html40">
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
WELCOME <?=$_SESSION['user']?></br>
<title> emc promo 1</title>
<meta http-equiv="Content-type" content="text/html;charset=utf-8" />
</head>
<body>
<?PHP
echo '<html><body><table><tr>';
while ($i < mysql_num_fields($t))
{
$meta = mysql_fetch_field($t);
echo '<td>' . $meta->name . '</td>';
$i = $i + 1;
}
echo '</tr>';
$i = 0;
while ($row = mysql_fetch_row($t))
{
echo '<tr>';
$count = count($row);
echo $count;
$y = 0;
while ($y < $count)
{
$c_row = current($row);
echo '<td>' . $c_row . '</td>';
echo "</br>";
next($row);
$y = $y + 1;
}
echo '</tr>';
$i = $i + 1;
}
echo '</table></body></html>';
mysql_free_result($t);
}
}{echo "there is no data";}*/
}
?``>
</body>
</html>
//我在查询中使用COUNT .........在我的结果中我得到一个数组格式但我需要数据库中的唯一值。它将计算数据库中的值和然后像我在下面写的那样显示它 我需要这个结果 新德里= 4 兰契= 2 法里达巴德= 3 但我得到city = 9 //
答案 0 :(得分:0)
您是否可以使用数据库结构来更好地理解数据。
如果我正在思考你想要得到一个值在数据库中的行号,这应该有效:
SELECT a.name, @curRow := @curRow + 1 AS row_number FROM contacts a JOIN (SELECT @curRow := 0) r
这将输出一个名为'row_number'的列,其中包含实际的行号 - (我刚刚使用了我运行的本地数据库来试用它)
编辑:
此查询将返回城市以及使用该城市分配的用户数:
SELECT city.name, COUNT(*) AS user_count FROM users INNER JOIN city ON users.city = city.id GROUP BY city
我做了如下测试:
$conn = mysqli_connect('localhost', 'root', 'root', 'test');
$query = mysqli_query($conn, "SELECT city.name, COUNT(*) AS user_count FROM users INNER JOIN city ON users.city = city.id GROUP BY city");
print '<ul>';
while($row = mysqli_fetch_array($query)):
print '<li>'.$row['name'].' - Users = '.$row['user_count'].'</li>';
endwhile;
print '</ul>';
输出如下: