Question

使用AWK增加日期

大家好，我需要你的帮助。我有一个文件“test.csv”，我想增加“6个月”和“10天”的日期，以便我得到以下输出：

test.csv：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE"

输出test-increment-10days.csv：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-05-17 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-05-19 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-05-20 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-05-21 12:02:07"

输出test-increment-6months.csv：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-11-07 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-11-09 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-11-10 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-11-11 12:02:07"

我已尝试使用此命令：

awk -F“\”，\“”'{{cmd =“date \”+％Y-％m-％d％T \“ - d \”“$ 3”+ 10天\””; cmd | getline datum;关闭（CMD）; print $ 0“，”“”datum“\”“}}'test.csv＆gt;测试增量-10days.csv

awk -F“\”，\“”'{{cmd =“date \”+％Y-％m-％d％T \“ - d \”“$ 3”+ 6个月\””; cmd | getline datum;关闭（CMD）; print $ 0“，”“”datum“\”“}}'test.csv＆gt;测试增量-6months.csv

但我得到了错误的输出。

测试递增-10days.csv：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-05-08 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-05-10 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-05-11 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-05-12 12:02:07"

测试递增-6months.csv：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-06-07 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-06-09 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-06-10 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-06-11 12:02:07"

“test-increment-10days.csv”中的日期仅增加一天，而“test-increment-6months.csv”中的日期仅增加一个月。希望有人可以提供帮助。

Answer 1

试试这个：

awk -F"\",\"" '{cmd="date -d \"$(date -d \""$3"\")+10days\" \"+%Y-%m-%d %T\"";cmd | getline datum; close(cmd); print $0 ",\""datum"\""}' test.csv > test-increment-10days.csv

基础日期命令的示例是：

date -d "$(date -d '2013-05-07 16:02:07')+10days" "+%Y-%m-%d %T"

有两个date命令。内部date创建具有指定值的日期。然后添加10天。外部日期创建一个新的递增日期并对其进行格式化。

Answer 2

这是使用GNU awk的一种方式。您首先需要将您的需求转换为秒。或者，写一些awk来执行此操作。这应该让你开始运行：

awk -f script.awk test.csv

script.awk的内容：

BEGIN {
    FPAT = "([^,]+)|(\"[^\"]+\")"
    OFS=","
}

{
    string = "\"(....)-(..)-(..) (..):(..):(..)\""
    format = "\\1 \\2 \\3 \\4 \\5 \\6"

    date_spec = gensub(string, format, "", $3)
    timestamp = mktime(date_spec)

    # 10 days = 864000 seconds
    # 6 months = 15638400 seconds

    # uncomment one of the following:
#   new_stamp = "\"" strftime("%F %T", timestamp + 864000) "\""
#   new_stamp = "\"" strftime("%F %T", timestamp + 15638400) "\""

    print $0, new_stamp
}

结果：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-05-17 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-05-19 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-05-20 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-05-21 12:02:07"

结果：

"000001","TEST1","2013-05-07 16:02:07","ACTIVE","2013-11-04 16:02:07"
"000003","TEST3","2013-05-09 16:02:07","ACTIVE","2013-11-06 16:02:07"
"000004","TEST4","2013-05-10 16:02:07","ACTIVE","2013-11-07 16:02:07"
"000005","TEST5","2013-05-11 12:02:07","ACTIVE","2013-11-08 12:02:07"

Answer 3

使用较少引用并使用简化的awk 'BEGIN { FPAT = "([^,]+)|(\"[^\"]+\")" OFS="," } { gsub(/["]/,"",$3); cmd = "date -d \""$3" 10 days\" \"+%Y-%m-%d %I:%M:%S %p\"" } { cmd|getline D; close(cmd); $3="\042"D"\042" }1' file构造的dogbane's answer的替代版本将是

awk 'BEGIN {
    FPAT = "([^,]+)|(\"[^\"]+\")"
    OFS=","
}
{   
    gsub(/["]/,"",$3);
    cmd = "date -d \""$3" 6 months\" \"+%Y-%m-%d %I:%M:%S %p\"" 
}
{
    cmd|getline D; close(cmd);
    $3="\042"D"\042"
}1' file

将持续6个月

cmd

所做的增强是：

在形成用于日期计算的命令字符串getline时使用较少的引号，这使得在awk的{{1}}函数中使用起来很优雅。
无需使用date -d<date-string> 10 days运算符即可使用+。
添加FPAT正则表达式构造以更严格地解析各个CSV字段。

用AWK增加日期几天和几个月

3 个答案: