我正在为ustream开发一个API,它返回以下数组
Array
(
[results] => Array
(
[0] => Array
(
[id] => 33756327
[userName] => sachintaware
[title] => Mobile record
[protected] =>
[description] => Recorded on my Android phone.
[createdAt] => 2013-06-03 03:29:38
[rating] => 0.000
[lengthInSecond] => 371.544
[totalViews] => 5
[codecIsForLiveHttp] =>
[url] => http://www.ustream.tv/recorded/33756327
[embedTag] =>
[liveHttpUrl] =>
[imageUrl] => Array
(
[small] => http://static-cdn2.ustream.tv/videopic/0/1/33/33756/33756327/1_14659377_33756327_120x90_b_1:2.jpg
[medium] => http://static-cdn2.ustream.tv/videopic/0/1/33/33756/33756327/1_14659377_33756327_320x240_b_1:2.jpg
)
[sourceChannel] => Array
(
[id] => 14659377
[url] => http://www.ustream.tv/channel/14659377
)
)
[1] => Array
(
[id] => 33756481
[userName] => sachintaware
[title] => gobiggitest
[protected] =>
[description] => gobiggitest
[createdAt] => 2013-06-03 03:37:49
[rating] => 0.000
[lengthInSecond] => 647.580
[totalViews] => 11
[codecIsForLiveHttp] =>
[url] => http://www.ustream.tv/recorded/33756481
[embedTag] =>
[liveHttpUrl] =>
[imageUrl] => Array
(
[small] => http://static-cdn2.ustream.tv/videopic/0/1/33/33756/33756481/1_14659377_33756481_120x90_b_1:3.jpg
[medium] => http://static-cdn2.ustream.tv/videopic/0/1/33/33756/33756481/1_14659377_33756481_320x240_b_1:3.jpg
)
[sourceChannel] => Array
(
[id] => 14659377
[url] => http://www.ustream.tv/channel/14659377
)
)
这是我用来浏览数组的函数,因为我想获取[id] => 14659377
里面的sourceChannel
。但是我得到一个空值作为返回值。这是什么错误我正在做?有人可以帮我吗?
$getUsername = array();
function recursion($array) {
foreach ($array as $key => $value) {
if($key==='sourceChannel'){
$getId = $value['id'];
//print_r($getId);
return $getId;
}
if (is_array($value))
recursion($value);
}
}
$getUsername=recursion($resultsArray);
print_r($getUsername);
答案 0 :(得分:4)
您的代码存在缺陷,因为您需要更改
recursion($value);
进入
return recursion($value);
返回将把答案带回呼叫者,直到到达第一个呼叫者。
修改强> 这里的教训是你的函数应该总是返回一个值。所以这里有一些更详细的说明:
function recursion($array) {
if (!is_array($array)) // check if what you're getting is an array!
return null;
foreach ($array as $key => $value) {
if($key==='sourceChannel') {
return $value['id'];
}
if (is_array($value)) {
$result = recursion($value);
if ($result !== null) {
return $result;
}
}
}
return null; // this happens if all recursions are done and sourceChannel was not found
}
答案 1 :(得分:1)
试试这个
foreach ($array['results'] as $key => $value) {
if($key == "sourceChannel"){
$getId = $value['id'];
//print_r($getId);
return $getId;
}
}
答案 2 :(得分:1)
你从递归调用返回时没有做任何事情。 它比简单地返回它要复杂一点,因为如果我们真的发现了什么,你只想要级联出来。
试试这个:
function recursion($array) {
foreach ($array as $key => $value) {
if($key==='sourceChannel') {
return $value['id'];
}
if (is_array($value)) {
$rc = recursion($value);
if (!is_null($rc)) return $rc;
}
}
return null;
}
首先,我将return null;
添加到函数的末尾 - 如果我们没有找到任何内容,则返回null。
然后,当我递归时,我检查返回值...如果它是非空的,这意味着我们找到了一些东西,我们想要返回它。如果它为null,我们不想要返回 - 我们希望继续循环。
答案 3 :(得分:1)
您可以使用迭代器使您的函数更容易:
function findSourceChannel($array)
{
foreach (new RecursiveIteratorIterator(new RecursiveArrayIterator($array)) as $key => $value) {
if ($key == 'sourceChannel') {
return $value['id'];
}
}
return null;
}
那就是说,我不确定你为什么不能这样做一个搜索:
foreach ($array['results'] as $result) {
if (isset($result['sourceChannel'])) {
return $result['sourceChannel']['id'];
}
}
return null;