Question

我目前在我的网站上有一个表格，但我需要在表格中的类别旁边有一个图标或其他内容，以使值按字母顺序提升，我不知道如何做到这一点我看了

enter image description here

这是我的代码 - （是的我知道它的不安全w / mysql_connect）

<?php       
    $username="dfgdfg";
    $password="dfgdfg";
    $database="dfg";
    mysql_connect(localhost,$username,$password);
    @mysql_select_db($database) or die( "Unable to select database");

    if (isset($_POST['search']))
    {
        $columbname = $_POST['selectitem'];
        $searchterm  = $_POST['searchterm'];
        $query="SELECT * FROM transactions WHERE agentclient  = '$agentclient' AND $columbname LIKE '%$searchterm%'";
        $result = mysql_query ($query) or die(mysql_error());
    }
    else
    {
        $query="SELECT * FROM transactions WHERE agentclient  = '$agentclient'";
        $result = mysql_query ($query) or die(mysql_error());
    }

    $num=mysql_numrows($result);
    mysql_close();
?>

<table width="98%" border="0" align="center" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
    <tr valign="bottom" bgcolor="#000000">
        <td width="24"><span class="style1b"><strong>No.</strong></span></td>
        <td width="105"><span class="style1b"><strong>Date</strong></span></td>
        <!--<td width="57"><span class="style1b"><strong>Agent/client</strong></span></td>-->
        <td width="120"><span class="style1b"><strong>Property/Description</strong></span></td>
        <td width="199"><span class="style1b"><strong>Transaction type </strong></span></td>
        <td width="235"><span class="style1b"><strong>Applicable document </strong></span></td>
        <td width="58"><span class="style1b"><strong>Received</strong></span></td>
        <td width="58"><span class="style1b"><strong>Paid</strong></span></td>
    </tr>

<?php

    $i=0;
    while ($i < $num) {

    $f1=mysql_result($result,$i,"id");
    $f2=mysql_result($result,$i,"date");
    //$f3=mysql_result($result,$i,"agentclientt");
    $f4=mysql_result($result,$i,"propertydescription");
    $f5=mysql_result($result,$i,"transactiontype");
    $f6=mysql_result($result,$i,"applicabledocument"); 
    $f7=mysql_result($result,$i,"received");
    $f8=mysql_result($result,$i,"paid");

?>
    <tr valign="top" bgcolor="#FFFFFF">
        <td><?php echo $f1; ?></td> <!--id-->
        <td><?php echo $f2; ?></td> <!--date-->
        <!-- <td><?php //echo $f3; ?></td> --><!--agent/client-->
        <td><?php echo $f4; ?></td> <!--desc-->
        <td><?php echo $f5; ?></td> <!--type-->
        <td><a href="/manage/clientdoc/<?php echo $f6; ?>"><?php echo $f6; ?></a></td> <!--document-->
        <td><?php echo $f7; ?></td> <!--recived-->
        <td><?php echo $f8; ?></td> <!--paid-->
    </tr>    

<?php
    $i++;
    }
?>

</table>

Answer 1

如果你的表有大量的行，不要使用javascript排序。使用服务器端排序。用于服务器端排序的参考链接 - http://forums.phpfreaks.com/topic/276091-help-with-search-sorting-and-pagination/

Answer 2

将您的更改为...您可以根据字段名称对数据进行排序..

按字段名ASC排序---或---按字段名DESC订购注意：默认排序是加入

 "SELECT * FROM transactions WHERE agentclient  = '$agentclient' AND $columbname LIKE '%$searchterm%' ORDER BY agentclient  ASC";

    $query="SELECT * FROM transactions WHERE agentclient  = '$agentclient' ORDER BY agentclient ASC ";

Answer 3

当您要检查哪个字段以及他在查询中选择和使用的排序类型时，获取图标添加参数的链接

ORDER BY ASC或ORDER BY DESC

例如

SELECT * FROM transactions WHERE agentclient  = '$agentclient' ORDER BY ASC

你提交它的方式是通过POST提交的，所以最好添加带字段的选择框和带排序类型的收音机/选择框

 <select name="sortby">
    <option value="agentClient">Client agent</option>
    <option value="name">Name</option>
 </select>
 <select name="orderby">
    <option value="desc" selected>Descending</option>
    <option value="asc">Ascending</option>
 </select>

然后在帖子中添加查询

$sorted_fields_avaiable = array('agentClient', 'name');
$sorting = "";
if(in_array($_POST['sortby'], $sorted_fields_avaiable)
{
   $sorting .= "ORDER BY ".$_POST['sortby'];
   if($_POST['orderby'] == 'asc') $sorting .= " ASC";
   else $sorting .= ' DESC';
}


$query = "SELECT * FROM transactions WHERE agentclient  = '$agentclient' $sorting";

请记住，这只是为了向您展示想法，您应该考虑将 mysqli 或 pdo 与绑定参数和预备语句一起使用。

如何使表上的值上升或下降

3 个答案: