Question

我有一份清单。

可能的成员（x123，y123，z123，a123，b123，c123）.// 123是例子该“mylist”可以包含以x开头的成员，或者可以不包含。对于y，z，a，b，c也是如此。

If contains a member starts with x:
//Formula Contains X

If Not Contains a member starts with x:
//Formula Not Contains X

//same as all of x,y,z,a,b,c. But unlike a foreach, I must place the formulas at checking time, not after.

我该怎么做？

Answer 1

检查列表中的任何项目是否以“x”开头：

bool result = mylist.Any(o => o.StartsWith("x"))

检查没有项目以“x”列表开头：

bool result = !mylist.Any(o => o.StartsWith("x"));

Answer 2

您可以使用.Any from Linq

bool result = mylist.Any(o => o.StartsWith("x"));

这将迭代列表并告诉您是否至少有一个元素以“x”开头

Answer 3

List<string> formula = new List<string> { "x123", "y123" };
string variable = "x";
bool containsVariable = formula.Any(s => s.StartsWith(variable));

Answer 4

public void Process(List<string> list, string key)
{
    if (list.Any(i => i.StartsWith(key)))
    {
        //Formula Contains key
    }
    else
    {
        //Formula Not Contains key
    }
}

然后你可以打电话

List<string> list = new List<string> { "x123", "y123", "z123", "a123", "b123", "c123"};
Process(list, "x");
Process(list, "a");

在List <string>？</string>中使用StartsWith和Contains

4 个答案: