Question

假设我有一个data.table

set.seed(1) # to make the example reproducible
ex<-data.table(AAA=runif(100000),
               BBB=runif(100000),
               CCC=runif(100000),
               DDD=runif(100000),
               FLAG=c(rep(c("a","b","c","d","e"),200000)))

我想从每个其他列的AAA列中减去，然后从BBB每个剩余列（FLAG除外）等减去，以便输出看起来像......

ex[,list(AAA_BBB=AAA-BBB,
         AAA_CCC=AAA-CCC,
         AAA_DDD=AAA-DDD,
         BBB_CCC=BBB-CCC,
         BBB_DDD=BBB-DDD,
         CCC_DDD=CCC-DDD)]

是否有data.table语法可以干净地执行此操作而不知道有多少列或它们的名称是什么？

Answer 1

循环使用data.table中的组合：

comblist <- combn(names(ex)[-5],2,FUN=list)
res2 <- ex[,lapply(comblist,function(x) get(x[1])-get(x[2]))]

setnames(res2,names(res2),sapply(comblist,paste,collapse="_"))

Answer 2

包含combn和apply的解决方案：

cc <- combn(colnames(ex)[1:4], 2)
apply(cc, 2, function(x)ex[[x[1]]]-ex[[x[2]]])

给出前5行：

             [,1]         [,2]       [,3]        [,4]        [,5]         [,6]
 [1,] -0.43500930 -0.520148152  0.1602265 -0.08513885  0.59523580  0.680374655
 [2,] -0.32964090 -0.153303302 -0.3807295  0.17633760 -0.05108855 -0.227426149
 [3,]  0.25991705 -0.079679566  0.2040904 -0.33959662 -0.05582670  0.283769917
 [4,]  0.35585252  0.153083047  0.2382553 -0.20276948 -0.11759719  0.085172292
 [5,] -0.67081018 -0.116543468 -0.3413471  0.55426671  0.32946305 -0.224803663

修改

正如Arun所说，combn可以采用函数参数，因此更好的解决方案是

res <- combn(colnames(ex)[1:4], 2, function(x) ex[[x[1]]] - ex[[x[2]]])
colnames(res) <- combn(colnames(ex)[1:4], 2, paste, collapse="_")
as.data.table(res)

            AAA_BBB     AAA_CCC     AAA_DDD     BBB_CCC     BBB_DDD     CCC_DDD
      1: -0.4350093 -0.52014815  0.16022650 -0.08513885  0.59523580  0.68037465
      2: -0.3296409 -0.15330330 -0.38072945  0.17633760 -0.05108855 -0.22742615
      3:  0.2599171 -0.07967957  0.20409035 -0.33959662 -0.05582670  0.28376992
      4:  0.3558525  0.15308305  0.23825534 -0.20276948 -0.11759719  0.08517229
      5: -0.6708102 -0.11654347 -0.34134713  0.55426671  0.32946305 -0.22480366
     ---                                                                       
 999996: -0.8450458 -0.47951267 -0.30333929  0.36553310  0.54170648  0.17617338
 999997: -0.5778393 -0.01784418 -0.24353237  0.55999516  0.33430697 -0.22568819
 999998:  0.7127352  0.82554276  0.01258673  0.11280758 -0.70014846 -0.81295604
 999999: -0.6693544 -0.42335069 -0.81080852  0.24600375 -0.14145408 -0.38745783
1000000: -0.8511655 -0.23341818 -0.15830584  0.61774732  0.69285966  0.07511234

从R data.table中减去每列的每列

2 个答案: