我的mysql中有三个表 * book_category，books和book_pictures * 。我希望通过修改 获取每本书类别 订单的最新书籍。我使用此查询来获取最新的书籍，它运行正常。
select * from (select * from books ORDER BY amended DESC) AS x GROUP BY book_sub_category_id
但我想加入我的book_pictures表，所以我得到book_pictures网址来显示图书图片。如何编写查询以从book_pictures表中获取最新的书籍？下面我将向您展示表格的结构。
book_category
+-------------+-----------------+
|category_id | category_name |
|-------------------------------|
| ca | custom Act |
| ct | Custom Tarif |
|-------------+-----------------+
books
+-------------+-----------------+-----------------+--------------------------+
| book_id | category_id | name | amended |
|-------------------------------|-----------------+--------------------------|
| 01 | ca | custom Act | 01-06-2011 |
| 02 | ca | custom Act | 01-06-2012 |
| 03 | ca | custom Act | 01-06-2013 |
| 04 | ct | custom tarif | 01-07-2011 |
| 05 | ct | custom tarif | 01-07-2012 |
| 06 | ct | custom tarif | 01-07-2013 |
+-------------+-----------------+-----------------+--------------------------+
book_pictures
+-------------+-----------------+-----------------+--------------------------+
| picture_id | book_id | small_url | large_url |
|-------------------------------|-----------------+--------------------------|
| p1 | 01 | url | url |
| p2 | 02 | url | url |
| p3 | 03 | url | url |
| p4 | 04 | url | url |
| p5 | 05 | url | url |
| p6 | 06 | url | url |
+-------------+-----------------+-----------------+--------------------------+
答案 0 :(得分：1)
使用左连接，
我认为这样可行，但没有运行它。
SELECT * FROM (
SELECT b.*,
p.large_url
FROM books b
LEFT JOIN book_pictures p
ON b.book_id = p.book_id
ORDER BY b.amended DESC
) AS x
GROUP BY book_sub_category_id