Question

DEMO 这个函数在firefox中不起作用，但100％在chrome中工作。这是什么原因？

我创建了一个js代码来保存元素css以供以后使用。它正在使用chrome而不是在firefox中为什么会这样？

function css(a){
    var sheets = document.styleSheets, o = {};
    for(var i in sheets) {
        var rules = sheets[i].rules || sheets[i].cssRules;
        for(var r in rules) {
            if(a.is(rules[r].selectorText)) {
                o = $.extend(o, css2json(rules[r].style), css2json(a.attr('style')));
            }
        }
    }
    return o;
}

function css2json(css){
        var s = {};
        if(!css) return s;
        if(css instanceof CSSStyleDeclaration) {
            for(var i in css) {
                if((css[i]).toLowerCase) {
                    s[(css[i]).toLowerCase()] = (css[css[i]]);
                }
            }
        } else if(typeof css == "string") {
            css = css.split("; ");          
            for (var i in css) {
                var l = css[i].split(": ");
                s[l[0].toLowerCase()] = (l[1]);
            };
        }
        return s;
    }

var style = css($("#elementToGetAllCSS"));
$("#elementToPutStyleInto").css(style);
var style = css($("#elementToGetAllCSS1"));
$("#elementToPutStyleInto1").css(style);

Answer 1

Firefox中存在冲突，现在已修复错误

(function($){
    $.fn.getStyleObject = function(){
        var dom = this.get(0);
        var style;
        var returns = {};
        if(window.getComputedStyle){
            var camelize = function(a,b){
                return b.toUpperCase();
            };
            style = window.getComputedStyle(dom, null);
            for(var i = 0, l = style.length; i < l; i++){
                var prop = style[i];
                var camel = prop.replace(/\-([a-z])/g, camelize);
                var val = style.getPropertyValue(prop);
                returns[camel] = val;
            };
            return returns;
        };
        if(style = dom.currentStyle){
            for(var prop in style){
                returns[prop] = style[prop];
            };
            return returns;
        };
        return this.css();
    }
})(jQuery)

var styles = $("#elementToGetAllCSS").getStyleObject();
$("#elementToPutStyleInto").css(styles);
var styles1 = $("#elementToGetAllCSS1").getStyleObject();
$("#elementToPutStyleInto1").css(styles1);

DEMO

这个功能在firefox中不起作用

1 个答案: