Question

我有这样的文字

Hello. @b this is text 1 #u user1

我想使用正则表达式来提取

This is text 1
user1

我的第一次尝试是检测@，＃signs然后将这些文本记录到StringBuilder中。但是，这是一个EditText，用户可以删除一些字符，我不得不从stringbuilder中删除它。最后，它变得越来越复杂，所以我决定找到另一个解决方案。

我的问题是：当命令（@ b，＃u，＃b，@ u）可用时，如何提取这些文本？例如：

Hello. @b this is text 1 => [This is text 1]
Hello. @b this is text 1 #u user1 => [This is text 1] [user1]
Hello. @u user1 => [user1]

我的第二次尝试：

 Pattern pattern = Pattern.compile("@b (.+) #u (.+)");
 Matcher mat = pattern.matcher(charSequence);
 while (mat.find()) {
      Logger.write("Matcher "+mat.group(1));
 }

但它仅适用于特定情况@b和#u

Answer 1

正则表达式

Pattern regex = Pattern.compile("(?<=[@#][bu]\\s)(?:(?![@#][bu]).)*");

<强>解释

(?<=    # Assert that this can be matched before the current position:
 [@#]   # an "@" or a "#"
 [bu]   # a "b" or a "u"
 \\s    # a whitespace character
)       # End of lookbehind assertion
(?:     # Then match...
 (?!    #  (as long as we're not at the start of the sequence
  [@#]  #  "@" or "#"
  [bu]  #  and "b" or "u"
 )      #  End of lookahead)
 .      # any character
)*      # any number of times

使用正则表达式在命令后提取文本

1 个答案: