Question

我有以下信息，但只有时间没有日期（时间连续），但我有日期基点。

time T1 T2 T3 T4
---------------------------------------------------------------------
14:36:11.000 24 28 23 35
20:46:20.000 27 28 27 32
00:07:33.000 24 27 23 38
01:36:20.000 94 28 27 32
03:46:50.000 24 28 23 37
07:58:20.000 64 58 27 32
15:29:25.000 24 23 27 32
01:15:32.000 44 28 27 39

如果我现在第一个Row的日期时间是'2013-06-03 14：36：11.000'。我怎样才能获得这些数据：

Datetime T1 T2 T3 T4
---------------------------------------------------------------------
2013-06-03 14:36:11.000 24 28 23 35
2013-06-03 20:46:20.000 27 28 27 32
2013-06-04 00:07:33.000 24 27 23 38
2013-06-04 01:36:20.000 94 28 27 32
2013-06-04 03:46:50.000 24 28 23 37
2013-06-04 07:58:20.000 64 58 27 32
2013-06-04 15:29:25.000 24 23 27 32
2013-06-05 01:15:32.000 44 28 27 39

Answer 1

此解决方案适用于MySql：

SELECT (@var:=if(time(@var)<=b.time,timestamp(date(@var),b.time),
     timestamp(date(date_add(@var, interval 1 day)),b.time))) as Datetime , 
     b.T1,b.T2,b.T3,b.T4
FROM test.YOURTABLE b, (select @var:='2013-06-03 00:00:00') a

Answer 2

试试这个 -

<强>查询：

DECLARE @temp TABLE
(
      [time] VARCHAR(12)
    , T1 INT
    , T2 INT
    , T3 INT
    , T4 INT
)

INSERT INTO @temp ([time], T1, T2, T3, T4)
VALUES 
    ('14:36:11.000', 24, 28, 23, 35),
    ('20:46:20.000', 27, 28, 27, 32),
    ('00:07:33.000', 24, 27, 23, 38),
    ('01:36:20.000', 94, 28, 27, 32),
    ('03:46:50.000', 24, 28, 23, 37),
    ('07:58:20.000', 64, 58, 27, 32),
    ('15:29:25.000', 24, 23, 27, 32),
    ('01:15:32.000', 44, 28, 27, 39)

DECLARE @Date DATETIME = '2013-06-03'

;WITH cte AS 
(
    SELECT 
          tt = [time]
        , rn = ROW_NUMBER() OVER (ORDER BY (SELECT 1))
        , T1, T2, T3, T4
    FROM @temp t
),
cte2 AS 
(
    SELECT t1.*, [shift] = 0 
    FROM cte t1
    WHERE t1.rn = 1

    UNION ALL

    SELECT cte.*, [shift] = 
                        CASE WHEN cte2.tt > cte.tt 
                            THEN [shift] + 1 
                            ELSE [shift] 
                        END 
    FROM cte2
    JOIN cte ON cte2.rn = cte.rn - 1
)
SELECT [time] = DATEADD(DAY, shift, @Date + ' ' + tt), T1, T2, T3, T4 
FROM cte2

<强>结果：

time                    T1          T2          T3          T4
----------------------- ----------- ----------- ----------- -----------
2013-06-03 14:36:11.000 24          28          23          35
2013-06-03 20:46:20.000 27          28          27          32
2013-06-04 00:07:33.000 24          27          23          38
2013-06-04 01:36:20.000 94          28          27          32
2013-06-04 03:46:50.000 24          28          23          37
2013-06-04 07:58:20.000 64          58          27          32
2013-06-04 15:29:25.000 24          23          27          32
2013-06-05 01:15:32.000 44          28          27          39

关于SQL与时间过程

2 个答案: