为每个数据集命名

时间:2013-06-03 22:48:48

标签: python list parsing loops output

所以我有一个代码

print
latOne = dL[1][3] 
lonOne = dL [1][4] 
x = [calculateDistance(latOne, lonOne, latTwo, lonTwo ) for latTwo, lonTwo in zip(latitude, longitude)]
print x

这会在带有输出

的列表中生成距离值
[0.0, 3043.004178666758, 21558.2996208357, 40246.748450913066, 40908.82213277263, 43786.0579097594, 67781.1426515405, 79693.11338661514, 65046.35819797423, 92804.01912347642]

现在每个距离都基于来自单独点(具有已定义名称)的坐标 即

Sydney (-20.7, 100) 
Melbourne (-20, 120)

所以我的代码将距离确定并产生距离列表。我想要做的是设置结构,以便打印距离及其相关的点名称。即从悉尼的纬度和长度计算距离,然后输出

Distance to Syndey is output ..., Distance to Melbourne is output, and so on.

如果您需要更多我的代码帮助,请告诉我。

编辑:

这是完整的脚本代码。

import math
import csv
def calculateDistance( latOne, lonOne, latTwo, lonTwo ):


from decimal import Decimal
latOne, lonOne, latTwo, lonTwo = [Decimal(x) for x in (latOne, lonOne, latTwo,lonTwo)]
DISTANCE_CONSTANT = 111120.0
 coLat = math.fabs(lonOne - lonTwo)
 alpha = 90 - latTwo
 beta  = 90 - latOne

 cosAlpha = math.cos(math.radians(alpha))
 cosBeta  = math.cos(math.radians(beta))
 sinAlpha = math.sin(math.radians(alpha))
 sinBeta  = math.sin(math.radians(beta))
 cosC     = math.cos(math.radians(coLat))

 cos_of_angle_a = (cosAlpha * cosBeta)
 cos_of_angle_b = (sinAlpha * sinBeta * cosC)
 cos_of_angle_c = cos_of_angle_a + cos_of_angle_b
 angle          = math.degrees(math.acos(cos_of_angle_c))
 distance       = angle * DISTANCE_CONSTANT
 return distance

stations = []
latitude = []
longitude = []
with open('data.csv', 'rU') as input: 
      dL= list(csv.reader(input))
      sL = [row[4] for row in dL[1:]]
      longitude.extend(sL)
      sL1 = [row[3] for row in dL[1:]]
      latitude.extend(sL1)
      sL2 = [row[1] for row in dL[1:]]
      stations.extend (sL2)

data = []
print "Station Coordinates" 
for i in range(0, len(latitude)):
    print str(stations[i]) + "(" + str(latitude[i]) + "," + str(longitude[i]) + ")"
    ab = str(stations[i]) + "(" + str(latitude[i]) + "," + str(longitude[i]) + ")"
    data.append(ab) 

print stations        

print
latOne = dL[1][3] 
lonOne = dL [1][4]
x = [calculateDistance(latOne, lonOne, latTwo, lonTwo ) for latTwo, lonTwo in zip(latitude, longitude)]
print x


print
lessthan, greaterthan = [], []
knowndistance = float(raw_input("Please type your radius"))
for v in x:
 if v <= knowndistance:
    lessthan.append(v)
 else:
    greaterthan.append(v)

print lessthan
print greaterthan

1 个答案:

答案 0 :(得分:0)

首先,您应该真正关注geopy.distance以及其他许多内置功能。是的,你已经编写了他们的算法之一,但它可能会有你需要的其他东西。

所以你打算在这里使用字典。如果您可以保存连接到车站的车站的经度和纬度,它将使您的生活变得非常轻松!

points = [[row[3],row[4]] for row in dL]
stations = [row[1] for row in dL]
my_dict = dict(zip(stations,points))

现在你有了一本字典,你可以按电台名称调用你的纬度和经度,然后以你以后可以回忆的方式存储它。我认为这就是完成代码所需的全部内容。如果不是,请发表评论,以便我可以相应地进行编辑。