Question

我正在使用的是一个区域鸟类的目击列表。有时同一只鸟被报告两次或三次。我想用它的名字对所有鸟类的所有目击进行分组，然后显示目击地点的位置名称。

到目前为止，这是我正在使用的，并且没有输出...在8小时......时间去寻求帮助。

以下是$ noteable的示例网址

http://ebird.org/ws1.1/data/notable/geo/recent?lng=-110.7576749&lat=32.4432180&detail=full&hotspot=true&dist=15&back=10

<?php
    $notexml = simplexml_load_file($noteable);
    $typesListXml = $notexml->xpath("result/sighting/com-name"); 

    if (!empty($typesListXml)) {
        $typesList = array();
        foreach ($typesListXml as $typeXml) {
            $typesList[] = (string)$typeXml;
        }
        $typesList = array_unique($typesList);

        $nameForType = array();
        foreach ($typesList as $type) {
            $rawData = $xml->xpath('result/sighting[com-name="' . $type . '"]');
            if (!empty($rawData)) {
                foreach ($rawData as $rawName) {
                    $nameForType[$type][] = $rawName->{'loc-name'};
                }
            }
        }

        var_dump($nameForType); // var_dump #4
    } 
}
?>

Answer 1

这样的事情怎么样？

<?php
    $noteable = 'http://ebird.org/ws1.1/data/notable/geo/recent?lng=-110.7576749&lat=32.4432180&detail=full&hotspot=true&dist=15&back=10';
    $xml = simplexml_load_file($noteable);
    $result = array();
    foreach ($xml->result->sighting as $sighting) {
        $location = (string) $sighting->{'loc-name'};
        $bird = (string) $sighting->{'com-name'};
        if (!isset($result[$bird])) $result[$bird] = array();
        $result[$bird][] = $location;
    }
    print_r($result);

对于上面包含的XML文件，它会生成以下输出：

Array
(
    [Buff-breasted Flycatcher] => Array
        (
            [0] => Mt. Lemmon--Rose Canyon and Lake
            [1] => Mt. Lemmon--Rose Canyon and Lake
            [2] => Mt. Lemmon--Rose Canyon and Lake
        )

    [Northern Goshawk] => Array
        (
            [0] => Mt. Lemmon--Rose Canyon and Lake
        )

)

如果您想避免报告同一只鸟的重复位置，可以在循环结束时添加array_unique次呼叫：

$result[$bird] = array_unique($result[$bird]);

使用PHP分组解析的XML元素

1 个答案: