Question

我试图在foreach循环中获取$ current_account，直到fooreach循环结束。我正在使用下一个函数，它给出了数组中的下一个元素，直到它到达结尾。如何在数组到达数组末尾时将其转到数组中的第一个元素？

$search_tags = array(
    "happy",
    "summer",
    "beach",
    "glasses",
    "umbrella",
    "funny",
    "people",
    "music",
    "rap"
);

$accounts = array(
    "account A",
    "account B",
    "account C"
);

foreach ($search_tags as $tag) {
    $current_account = current($accounts);
    print_r($current_account."\n");

};

所以在这种情况下结果应该是这样的：

帐户B. 帐户C. 帐户A. 帐户B. 帐户C. 帐户A. 帐户B. 帐户C. 帐户A

但我得到以下内容：

帐户B. 帐户C

Answer 1

使用InfiniteIterator

$accounts = new InfiniteIterator(new ArrayIterator($accounts));
$accounts->rewind();

foreach($search_tags as $tag) {
    echo ucfirst($accounts->current()), PHP_EOL;
    $accounts->next();
}

See Live Demo

Answer 2

还有其他简单的方法，例如通过索引访问帐户元素，具体取决于当前索引，如下所示;

foreach ($search_tags as $index => $tags) {
    print_r($accounts[$index % count($accounts)] . "\n");
}

哪些输出;

account A
account B
account C
account A
account B
account C
account A
account B
account C

PHP：获取数组的下一个值，直到foreach循环结束

2 个答案: