我是编程和C ++的新手，我开始制作一个有趣的小字符串类型游戏，它为用户提供了两个选项，但是在程序的最后部分，我无法输出一个独特的选项最终输入（makeCure） - 我只想在最后输出而不是通过程序输出。希望我有意义：/。我尝试过并尝试过，我尝试了更多的问题。我在下面的代码中显示了我确定问题所在。任何建议都会非常感激。
#include<iostream>
#include<string>
using std::string;
bool intro(void);
void room(bool enemy, bool data, bool cure, string description);
//player stats
string Name = "";
//enemy states
string enemyName = "";
//data stats
string dataName = "";
//Cure - Option in room7 only
string makeCure = "";
//room descriptions(string constructs)
const string room1 = "You enter the first town of infected Zombies.";
const string room2 = "You are overwelmed by Zombies, and plunder into the sewers to escape.";
const string room3 = "You make your way to safety and find yourself in the Central Town Hall.";
const string room4 = "You decide to venture into the local forest to find the finalingrediants";
const string room5 = "You venture further for the final ingrediant, into a nearby Cave.";
const string room6 = "Its time for you to face the Zombie General!!!";
const string room7 = "You work day and Night in the Labs to make the Cure.";
int main(void)
{
if(intro())
return 0;
dataName = "First Ingrediant- Zombie Rags with infected DNA";
enemyName = "Zombie Soldior";
room(true, true, false, room1);
enemyName = "Massive Zombie Rat";
room(true, false, false, room2);
dataName = "Seconed Ingrediant- StemCells";
enemyName = "Mutated Scientists";
room(true, true, false, room3);
dataName = "Third Magic-Mushrooms";
room(false, true, false, room4);
dataName = "Fourth Final Ingrediant - Coffee Beans";
enemyName = "Commander Zombie";
room(true, true, false, room5);
enemyName = "Zombie General";
room(false, true, false, room6);
return 0;
makeCure = "Elixier to Save the World";
room(false, false, true, room7);
return 0;
}
bool intro(void)
{
using std::cout;
using std::cin;
cout << "Brave Soul!!! What is your name?\n";
cin >> Name;
cout << "Ahh... " << Name << " You say.." << "How about Zombie Slayer?.. Good, glad we agree!\n";
cout << "Humanity is in need of your Help, "
<< "The world is being infected by the\n"
<< "ZD1678 ZOMBIE VIRUS \n"
<< "And we need to send you to Cape Town to stop the central spread.\n"
<< "Your task will be tough, but we know you can do it \n"
<< "Will you accept the challenge?\n\n";
cout << "1)Yes. \n"
<< "2)No. \n\n";
int response;
cin >> response;
return !(response ==1);
}
void room(bool enemy, bool data, bool cure, string description)
{
using std::cout;
using std:: cin;
while(true)
{
cout << description.c_str() << "\n\n";
int response = 0;
do
{
cout << "Shall Our Hero continue his Quest?\n";
if(enemy)
cout << "1) Attack the "
<< enemyName.c_str() << "\n";
else if(!enemy)
cout << "1) venture further....";
if(data)
cout << "2)Pick up the "
<< dataName.c_str() << "\n";
cin >> response;
/* Trying to create the last if that only kicks in at room7( string makeCure )
* that displays the option to make the cure
* This is where my Problem is.
* Iv tried anouther if
* and else
* and while and nothing works, its just messes up everything..
* badly
*/
} while(response < 1 || response > 2);
switch(response)
{
case 1:
if(enemy)
{
enemy = !enemy;
cout << "You slay the deadly "
<< enemyName.c_str() << "\n";
}
else if(!enemy)
return;
break;
case 2:
data = !data;
cout << "You pick up the "
<< dataName.c_str() << "\n";
break;
}
}
}
答案 0 :(得分：1)
您可能想要做的是每次写出列表并将其呈现给用户时动态生成可能事件的列表，然后您可以将响应与列表匹配以获得用户想要执行的操作。像这样：
enum EventType
{
ET_Enemy,
ET_Item,
ET_Cure,
ET_Continue,
ET_MAX
};
void room(bool enemy, bool data, bool cure, string description)
{
using std::cout;
using std:: cin;
int currentEventChoices[ET_MAX];
int numEventChoices;
while(true)
{
cout << description.c_str() << "\n\n";
int response = 0;
do
{
numEventChoices = 0;
cout << "Shall Our Hero continue his Quest?\n";
if(enemy)
{
cout << (numEventChoices+1) << ") Attack the "
<< enemyName.c_str() << "\n";
currentEventChoices[numEventChoices] = ET_Enemy;
numEventChoices++;
}
if(data)
{
cout << (numEventChoices+1) << ") Pick up the "
<< dataName.c_str() << "\n";
currentEventChoices[numEventChoices] = ET_Item;
numEventChoices++;
}
if(cure)
{
cout << (numEventChoices+1) << ") cure related string "
<< makeCure.c_str() << "\n";
currentEventChoices[numEventChoices] = ET_Cure;
numEventChoices++;
}
cout << (numEventChoices+1) << ") venture further....\n"; // note if this is only meant to be an option if there is no enemy, put it in an else after the if(enemy)
numEventChoices++;
cin >> response;
} while(response < 1 || response > numEventChoices);
switch(currentEventChoices[response-1])
{
case ET_Enemy:
enemy = !enemy;
cout << "You slay the deadly "
<< enemyName.c_str() << "\n";
break;
case ET_Item:
data = !data;
cout << "You pick up the "
<< dataName.c_str() << "\n";
break;
case ET_Cure:
//do cure stuff
break;
case ET_Continue:
return;
}
}
}
你遇到的麻烦是，每次你想要将选项号与事件匹配时，只使用非常静态的if / else语句，它会变得非常复杂和混乱，当只有有4个敌人与否，或数据与否。但是现在你要添加另一个带有治疗的分支，这样做真的很复杂。
答案 1 :(得分：0)
有点难以理解你需要什么，所以告诉我它是不是你想要的。
使用大括号和缩进可以真正帮助解决这个问题：
do {
cout << "Shall Our Hero continue his Quest?\n";
if (enemy) {
cout << "1) Attack the " << enemyName << "\n";
} else {
cout << "1) venture further....";
}
if (data) {
cout << "2) Pick up the " << dataName << "\n";
}
if (cure) {
cout << "2) take the " << makeCure << "\n";
}
cin >> response;
} while (response < 1 || response > 2);
并修复开关部分中的“案例2”：
case 2:
if (data) {
data = false;
cout << "You pick up the " << dataName << "\n";
} else if (cure) {
// fill in ...
}
break;
注意：
endl（来自std）而不是'\ n'。 cout << "hello" << endl; if(enemy) ... else if(!enemy)您不需要!enemy部分。它由else隐含。