Question

从以下四条记录中，我想选择第二条最新记录的OwnerId

ItemId  OwnerId Date
11477   20981   2013-05-13
11477   1       2013-05-21
11477   21086   2013-05-22 #this is the one I'm talking about
11477   3868    2013-05-24

如何去做？

Answer 1

这需要指定ItemID，

SELECT *
FROM   TableName
WHERE  ItemID = '11477'
ORDER  BY DATE DESC
LIMIT  1,1

SQLFiddle Demo

但是，如果您不想指定ItemID，并且希望获得每个ItemID的所有第二个最新记录，则可以使用相关子查询为每个创建序列号ItemID基于最新DATE，

SELECT  ItemId, OwnerID, Date
FROM
        (
            SELECT  A.ItemId, 
                    A.OwnerId, 
                    A.Date,
                    (
                        SELECT  COUNT(*)
                        FROM    tableName c
                        WHERE   c.ItemId = a.ItemId AND
                                c.Date >= a.Date) AS RowNumber
            FROM    TableName a
        ) x
WHERE   RowNumber = 2

SQLFiddle Demo

Answer 2

select ownerid
from your_table
order by date desc
limit 1, 1

Answer 3

我认为您可以ORDER BY日期降序，这将为您提供从较新到较旧的订单，然后LIMIT 1,1仅获取第二个结果，该结果应该是您要查找的结果< / p>

SELECT *
FROM table
ORDER BY date DESC
LIMIT 1,1

检索具有相同ID的第二个最新记录

3 个答案: