使用Django Formset进行文件上载问题

Question

我正在Django中编写一个应用程序，它使用DB中的文件路径引用将文件上传到文件系统。

我正在使用一个子对象来处理输入文件并将其存储在文件系统中。我在Django中使用formset也是如此。

这里的问题是我遇到了ValidationError

这里是 views.py

def trainmodule(request):
class RequiredFormSet(BaseFormSet):
    def __init__(self, *args, **kwargs):
        super(RequiredFormSet, self).__init__(*args, **kwargs)
        for form in self.forms:
            form.empty_permitted = False

TrainingContentFormSet = formset_factory(TrainingContentForm, max_num=10, formset=RequiredFormSet)

if request.method == "POST":
    tmform = TrainingModuleForm(request.POST)
    tcformset = TrainingContentFormSet(request.POST, request.FILES)
    module_save = tmform.save()
    for tc in tcformset:
        content_save = tc.save(commit=False)
        content_save = ModelWithFileField(file_field = request.FILES['file'])
        content_save.tmodule = module_save
        content_save.save()
    return HttpResponseRedirect('hello')
else:
    tmform = TrainingModuleForm()
    tcformset = TrainingContentFormSet()

return render(request, 'training-module.html', {'tmform': tmform, 'tcformset': tcformset})  

以下是相关的模型：

class TrainingModule(models.Model):
name = models.CharField(max_length=30)
description = models.TextField()
final_url = models.URLField()

def __unicode__(self):
    return self.name

class TrainingContent(models.Model):
inputfile = models.FileField(upload_to="input_documents/")
outputfile = models.FileField(upload_to='converted/')
name = models.CharField(max_length=50)
filehash = models.CharField(max_length=255)
desc = models.TextField()
tmodule = models.ForeignKey(TrainingModule)

def __unicode__(self):
    return self.name

这里是forms.py：

from security_awareness.models import TrainingModule, TrainingContent
from django.forms import ModelForm

class TrainingModuleForm(ModelForm):
    class Meta:
        model = TrainingModule
        fields = ['name', 'description']

class TrainingContentForm(ModelForm):
    class Meta:
        model = TrainingContent
        exclude = ('tmodule', )
        fields = ['name', 'desc', 'inputfile']

我对Python和Django都比较陌生。

任何帮助将不胜感激。感谢。