Question

所以我使用php构建了一个向导，其中一个表单要求用户上传图像。

我已经构建了所有内容，唯一的问题是我必须能够在我的一个if语句中说，如果表单是使用jquery的submit（）方法提交的。

所以这是在用户选择图像后在jquery中提交表单的代码。

var initUpload = function(){
    $('.filebutton').change(function(e){
        $("form").submit();
    });
};

这就是我的if语句的样子。

if($this->input->post('back')){

   //Tells me that the user clicked on the back button, and to go back 1 step in the wizard.    

}else if(???){

   //This is where I would like to say: if form was submitted with jquery.      

}else{

   //Else the user just clicked "next" and to continue normally.

}

我已经知道的事情：

使用$this->input->post('back')我可以使用带有value BACK的按钮来检查表单是否已提交。我var_dumped $this->input->post()但它只返回输入字段的值。

Answer 1

如上所述，我被要求发表评论作为答案，所以你去吧

if($this->input->post('back')){

//Tells me that the user clicked on the back button, and to go back 1 step in the wizard.    

}else if($_FILES['your_image_filed_name']){

//This is where I would like to say: if form was submitted with jquery.  
//you can use codeigniter's built in Upload libraray which v easy      

}else{

 //Else the user just clicked "next" and to continue normally.

 }

以下upload代码查看

   $config_logo_image = array(
    'allowed_types' => 'jpg|jpeg|gif|png',
    'upload_path' => UPLOAD_PATH,//root path for image
    'max_size' => 2000,
    );
$this->load->library('upload', $config_logo_image );                    
if($this->upload->do_upload('your_image_filed_name')){

$logo_image_data = $this->upload->data();

}

使用Codeigniter，如何通过jquery submit（）提交表单？

1 个答案: