Question

我有5张图片存储在一个文件夹中，他们的链接存储在数据库中。我想把它们放在每行三列的表格中。

<body>
<center>
<table border='1'>
<?php
$host="";
$username="";
$password="";
$db_name="fruits_db";
$tbl_name="fruits_tbl";
$connection=mysqli_connect("$host","$username","$password","$db_name");
if (mysqli_connect_errno())
{
    echo "The application has failed to connect to the mysql database server: " .mysqli_connect_error();
}
$result = mysqli_query($connection, "SELECT * FROM fruits_tbl")or die("Error: " . mysqli_error($connection));
$num_rows=mysqli_num_rows($result);
$rows =  $num_rows/3;

for($i=1; $i<=$rows ; $i++)
{
    echo "<tr>";
    for($j=1; $j<=3; $j++)
    {
        while($row = mysqli_fetch_array($result))
        {
            echo
            ("<td width='180px' height='200px'>"
             ."<div class = 'fruit_image'>"
             ."<img src='"
             .$row['fruit_image']
             ."'/>"
             ."</div>"
             ."<div class = 'fruit_title'>"
             .$row['fruit_name']
             ."</div>"
             ."</td>"
            );
        }
    }
    echo "</tr>";
}

mysqli_close($connection);
?>
</table>
</center>
</body>
</html>

我创建的上述代码包含两个FOR循环。该脚本应计算表中的行数，然后除以3（HTML表中每行的列数）。我想知道这个代码在哪里出错了。

Answer 1

在你的第一个for循环中使用while($row = mysqli_fetch_array($result)){}它会在你的第二次/第三次外循环运行之前遍历所有行。

这是另一种方法 -

$counter = 1;
// start 1st row
echo "<tr>";
while($row = mysqli_fetch_array($result)){
// if the 4th cell, end last row, and start new row
    if ($counter%3==1){
        echo "</tr><tr>";
    }
    echo
        "<td width='180px' height='200px'>"
        ."<div class = 'fruit_image'>"
        ."<img src='"
        .$row['fruit_image']
        ."'/>"
        ."</div>"
        ."<div class = 'fruit_title'>"
        .$row['fruit_name']
        ."</div>"
        ."</td>";
    // increase the counter
    $counter++;
}
// close the last row
echo "</tr>";

Answer 2

您正在遍历第一个表格单元格中的所有结果。尝试这样的事情：

for($i=1; $i<=$rows ; $i++) {
    echo "<tr>";
    for($j=1; $j<=3; $j++) {
        $row = mysqli_fetch_array($result);
        if ($row) {
            echo(
                "<td width='180px' height='200px'>"
                ."<div class = 'fruit_image'>"
                ."<img src='"
                .$row['fruit_image']
                ."'/>"
                ."</div>"
                ."<div class = 'fruit_title'>"
                .$row['fruit_name']
                ."</div>"
                ."</td>"
            );
        }
    }
    echo "</tr>";
}

Answer 3

如果您只想在每3条记录后用新行格式化显示，可以使用模数运算符：

$cntr = 0;
echo '<tr>';
while($row = mysqli_fetch_array($result)) {
   $cntr++;
   echo '
      <td width="180px" height="200px">
         <div class="fruit_image">
            <img src="'.$row['fruit_image'].'" />
         </div>
         <div class="fruit_title">'.$row['fruit_name'].'</div>
      </td>';
   if ($cntr % 3 == 0 && $cntr != $num_rows)
      echo '</tr><tr>';
}
echo '</tr>';

请注意，到目前为止提供的所有解决方案都可能会为您留下一个带有一个或两个td元素的最后一行。如果您需要空<td> </td>列，可以填写此内容。

Answer 4

    print "<center><table border=1>
        <tr>
        <td>id</td>
        <td>name</td>
        <td>company</td>
        <td>branch</td>
        <td>job title</td>
        <td>contact</td>
        <td>email</td>
        <td>mgs</td>
        </tr>";

    while($row=mysql_fetch_array($query))
    {
        print "<tr>";
       for ($i=0;$i<=(count($row)/2);$i++)
              {
               print "<td>$row[$i]</td>";
               } print"</tr>";
   }

    }
    else{echo " <p>No Records Found</p>";}

Answer 5

<?php
function studentTable($name,$grade){
echo "<tr> <td>$name</td><td>$grade</td></tr>";
}
?>
    <table style="width:100%" border="solid">
<tr>
<th>Name</th>
<th>Grade</th> 
 </tr>
 <?php studentTable("Sarah", 90) ?>

如何使用PHP在HTML中创建表

5 个答案: