Question

当我尝试使用一个任务编译我的线程池时出现以下错误：

错误：＆＃39; void ThreadPool :: enqueue（F）[with F = CConnection :: handle（）::]＆＃39;，使用本地类型声明＆＃39; CConnection :: handle（）::＆＃39;，但从未定义过 [-fpermissive]

这是线程池声明：

class ThreadPool {
public:
    ThreadPool(size_t);
    template<class F>
    void enqueue(F f);
    ~ThreadPool();
private:
    // need to keep track of threads so we can join them
    std::vector< std::unique_ptr<boost::thread> > workers;

    // the io_service we are wrapping
    boost::asio::io_service service;
    boost::asio::io_service::work working;
    friend class Worker;
};

这是函数，想要使用线程池来测试：

void CConnection::handle()
{
     ThreadPool pool(4);
     pool.enqueue([1]
    {
        std::cout << "hello " << 1 << std::endl;
        boost::this_thread::sleep(
            boost::posix_time::milliseconds(1000)
        );
        std::cout << "world " << 1 << std::endl;
    });
     char * databuffer;
     databuffer = new char[16];
     for(int i = 0;i<16;i++)
     {
      databuffer[i] = 0x00;
     }
     databuffer[0] = 16;
     databuffer[4] = 1;
     databuffer[8] = 1;
     databuffer[12] = 1;
     asynchronousSend(databuffer, 16);

}

以下是入队定义：

template<class F>
void ThreadPool::enqueue(F f)
{
    service.post(f);
}

有人能找到我做错的事吗？

Answer 1

ThreadPool.h头文件中是否有enqueue的定义？这是模板方法

所必需的

线程池编译错误

1 个答案: