Question

我刚刚发现isset函数不再适用于我的登录和注册表单。我很奇怪，所以我解除了我最近所做的一切，看它是不是造成了它，但没有运气。如果我删除了isset并替换为此;

if($_SERVER['REQUEST_METHOD'] == "POST"){

它有效！但是我在一个页面上有两个表单，所以我需要检查哪个表单已提交。

这是isset函数：

if (isset($_POST['submit_login'])) {

提交按钮只是让你知道它有正确的名称;

<input type="submit" name="submit_login" value="Login" class="buttonClassic"/>

注册表单的格式完全相同，但名称为submit_reg。

形式：

<form action="<?php echo htmlentities('Login'); ?>" method="post" id="login"> 
   <p class="p1">Already signed up? Log in</p><hr/>
   <label for="email">Your email address </label><input type="email" required name="email" placeholder="Email" class="text" id="email">
   <label for="password">Your password </label><input type="password"  name="pass" required placeholder="Password" class="text" id="password">
   <center><input type="submit" name="submit_login" value="Login" class="buttonClassic"/></center>
   <div class="center-align-text">
       <p class="p3"><a href="passreset.html">Forgotten your password?</a></p>
   </div>
</form>

注册表格：

<form action="<?php echo htmlentities('Login'); ?>" method="post" id="register" >
   <p class="p1">New to NBS? Sign up, it's free!</p><hr/>
   <label for="reg_email">What's your email address? </label><input type="email" name="email" required placeholder="Email" class="text" id="reg_email">
   <label for="reg_password">Choose a password </label><input type="password" required name="pass" placeholder="Password" class="text" id="reg_password">
   <label for="reg_password2">Re-type password </label><input type="password" required name="pass2" placeholder="Re-type password" class="text" id="reg_password2">
   <input type="checkbox" name="subscribed" value="subscribed" id="subscribed"><label for="subscribed">Yes, send me email updates from NewBorn Sounds. </label>
   <br/>
   <input type="checkbox" required="flag" name="terms" value="ticked" id="terms"><label for="terms">I agree to the <a href="Terms">terms & conditions</a>.</label>

   <center><input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic"></center>
</form>

如果您需要更多信息，请大声喊叫！

哦，我知道我可以将表单提交给外部PHP脚本，但我并不特别想这样做，因为我希望将用户输入错误输出到同一页面。我知道我可以使用ajax，我这样做，但我试图将javascript作为一个附加组件，而不是减少没有js的用户体验。

完整HTML：

<div id="login_form_wrapper">

<form action="Login" method="post" id="login" novalidate="novalidate"> 
   <p class="p1">Already signed up? Log in</p><hr>
   <label for="email">Your email address </label><input type="email" required="" name="email" placeholder="Email" class="text" id="email">
   <label for="password">Your password </label><input type="password" name="pass" required="" placeholder="Password" class="text" id="password">
   <center><input type="submit" name="submit_login" value="Login" class="buttonClassic"></center>
   <div class="center-align-text">
       <p class="p3"><a href="passreset.html">Forgotten your password?</a></p>
   </div>
</form> 


<form action="Login" method="post" id="register" novalidate="novalidate">
   <p class="p1">New to NBS? Sign up, it's free!</p><hr>
   <label for="reg_email">What's your email address? </label><input type="email" name="email" required="" placeholder="Email" class="text" id="reg_email">
   <label for="reg_password">Choose a password </label><input type="password" required="" name="pass" placeholder="Password" class="text" id="reg_password">
   <label for="reg_password2">Re-type password </label><input type="password" required="" name="pass2" placeholder="Re-type password" class="text" id="reg_password2">
   <input type="checkbox" name="subscribed" value="subscribed" id="subscribed"><label for="subscribed">Yes, send me email updates from NewBorn Sounds. </label>
   <br>
   <input type="checkbox" required="flag" name="terms" value="ticked" id="terms"><label for="terms">I agree to the <a href="Terms">terms &amp; conditions</a>.</label>

   <center><input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic"></center>
</form> 

</div>

Answer 1

也许你可以这样做：

if($_SERVER['REQUEST_METHOD'] == "POST"){ 
 if (isset($_POST['submit_login'])) { 
    //do something
 } else {
   //do something else
 }

}

Answer 2

表单操作需要是有效的网址，例如“/login.php”。

复选框具有给定的值（一旦选中），或者它们根本不显示。最好是仔细检查它们：“isset（$ _ POST ['mycheckbox']）＆amp;＆amp;'value'== $ _ POST ['mycheckbox']”。

向我们展示您用来评估表单的php。

Answer 3

这是怎么回事？

<input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic">
<?php
if($_POST['submit'] == 'Sign Up'){
  //do something
}
?>

PHP isset函数提交检查不起作用

3 个答案: