我的mysql数据库中有3个表:student, progress and subject
。当我尝试选择数据时:
SELECT progress.id, progress.mark, subject.pname FROM progress, subject WHERE progress.id_student = 1;
我得到下表:
id mark pname
1 5 Math
1 5 Physics
表格进度我只有一个条目:
id mark id_student id_subject
1 5 1 1
如何通过student_id
获得学生进度?
CREATE DATABASE students;
USE students;
CREATE TABLE student (
id int NOT NULL AUTO_INCREMENT,
name varchar(100) NOT NULL,
address varchar(60) NOT NULL,
byear int NOT NULL,
eyear int NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE subject (
id int NOT NULL AUTO_INCREMENT,
pname varchar(20) NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE progress (
id int NOT NULL AUTO_INCREMENT,
mark int NOT NULL,
id_student int NOT NULL,
id_subject int NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (id) REFERENCES student (id),
FOREIGN KEY (id) REFERENCES subject (id)
);
答案 0 :(得分:1)
SELECT progress.id, progress.mark, subject.pname
FROM progress LEFT OUTER JOIN subject ON (progress.id_subject= subject.id)
WHERE progress.id_student = 1;
答案 1 :(得分:1)
尝试
SELECT progress.id, progress.mark, subject.pname
FROM progress, subject
WHERE progress.id_student = 1 AND progress.id_subject = subject.id;