Question

我在数据库中有一个包含以下内容的临时表：

 userid | time              
--------|---------------------
 1      | 13-01-24 00:04:01 
 1      | 13-01-24 00:04:04 
 1      | 13-01-24 00:05:06 
 2      | 13-01-24 00:06:06 
 2      | 13-01-24 00:06:08

我想得到如下答案：

1,  0 second
1,  3 second
1,  62 second
2,  60 second
2,  2 second

我尝试了'TIMEDIFF'脚本（max(time)，min(time)），但它没有输出我想要的内容。请帮助，我正在使用PHP。

Answer 1

MySQL解决方案：

SET @prev_time = null;
SELECT userid, IFNULL(timediff(`time`,@prev_time), 0) diff,
       @prev_time := `time`
FROM mytable
ORDER BY time

SQLFIDDLE

Answer 2

PHP解决方案：

（同样是@Barmar的解决方案，但在php中）

<?php
$timearray = array("13-01-24 00:04:01", "13-01-24 00:04:04", "13-01-24 00:05:06", "13-01-24 00:06:06", "13-01-24 00:06:08");
$prevtimestamp = null;
foreach($timearray as $it) {
    $datetime = explode(" ", $it);
    $date = explode("-", $datetime[0]);
    $time = explode(":", $datetime[1]);
    $newtimestamp = mktime($time[0], $time[1], $time[2], $date[1], $date[0], $date[2]);
    if($prevtimestamp == null) $prevtimestamp = $newtimestamp;
    echo $newtimestamp - $prevtimestamp . " seconds";
    $prevtimestamp = $newtimestamp;
}
?>

PHP中的时间差异

2 个答案: