如何在参数中分配时间戳格式值？

Question

[Timestamp]
public byte[] Timestamp { get; set; }

如何为Timestamp分配虚拟值？

Answer 1

如果你只是想避免空值：

Timestamp = new byte[0];

Answer 2

试试这个： -

public class Time
{
    [Timestamp]
    private Lazy<byte[]> _timestamp=new Lazy<byte[]>();

    [Timestamp]
    public Lazy<byte[]> Timestamp
    {
        get
        {
            return _timestamp;
        }

        set { _timestamp = value; }
    }
}