Question

我想检索两个日期之间不同年份的列表。

例如，从25/12/2006到14/11/2013，结果应如下所示：

这在SQL Server中是否可行？

Answer 1

像1/2/2013这样的日期含糊不清：根据地区设置，它可以是2月1日或1月2日。所以在与数据库交谈时使用YYYY-MM-DD日期格式是个好主意。

您可以使用递归CTE生成数字列表：

; with  CTE as
        (
        select  datepart(year, '2006-12-25') as yr
        union all
        select  yr + 1
        from    CTE
        where   yr < datepart(year, '2013-11-14')
        )
select  yr
from    CTE

Example at SQL Fiddle.

Answer 2

在SQL Server 2008上测试

declare @smaller_date date = convert(date, '25/12/2006', 103)
declare @larger_date date = convert(date, '14/11/2013', 103)
declare @diff int
select @diff = DATEDIFF(YY, @smaller_date,  @larger_date)

;with sequencer(runner) as(
select 0 
union all
select sequencer.runner + 1 from sequencer
where runner < @diff
)
select YEAR(@smaller_date) + runner from sequencer

Answer 3

CREATE FUNCTION [dbo].Fn_Interval 
(   
    @p1 datetime2, 
    @p2 datetime2
)
RETURNS @dt TABLE 
(
    YearValue int not null
)
AS
BEGIN

    declare @start as int
    declare @end as int

    set @start = DATEPART(year, @p1);
    set @end = DATEPART(year, @p2);

    while (@start <= @end)
    begin
        INSERT @dt
        SELECT @start;
        set @start = @start + 1;
    end

    RETURN;
END

打开查询并尝试：

declare @p1 as datetime2;
declare @p2 as datetime2;

set @p1 = '2013-12-31';
set @p2 = '2020-05-05';

select *
from dbo.Fn_Interval(@p1, @p2)

Answer 4

首先，创建一个calendar table。然后你只需查询年份：

select distinct YearNumber
from dbo.Calendar
where [Date] between '20061225' and '20131114'
order by YearNumber

Answer 5

我的两分钱

由于OP的示例实际上只是一小部分值，因此我想得出一个答案，该答案不依赖于递归/循环或创建其他对象，例如函数/日期表。它只使用Top子句。

在SQL Server 2016上测试

DECLARE @startYear smallint;
SET @startYear = YEAR ('2006-12-25');

DECLARE @endYear smallint;
SET @endYear = YEAR('2013-11-14');

-- Top uses expression to bring in N number of rows. The (@startYear - 1) is to retain the start year
SELECT TOP (@endYear - (@startYear - 1)) COUNT([object_id]) OVER (ORDER BY [object_id]) + (@startYear - 1) -- Add initial start year to Count 
FROM sys.all_objects;

希望这是另一回事。

两个日期之间的不同年份列表

5 个答案: