CodeIgniter表单复选框的验证规则

时间:2013-05-31 09:36:16

标签: php codeigniter

我有一个带有复选框的表单,用于接受TOS。问题是我需要为此复选框添加自定义错误

    <form>

    <input type="text" name="fname" placeholder="Name" /><?php echo form_error('fname') ?>
    <input type="text" name="email" placeholder="Email" /><?php echo form_error('email') ?>
    <input type="text" name="password" placeholder="Password" /><?php echo form_error('password') ?>

    <input type="checkbox" name="accept_terms" value="yes" /> Accept TOS<br>
    <?php echo form_error('accept_terms') ?>

    </form>

PHP

<?php 

 $this->form_validation->set_rules('fname','First Name','trim|required|xss_clean');
 $this->form_validation->set_rules('email','Email','trim|required|xss_clean|valid_email');
 $this->form_validation->set_rules('password','Password','trim|required|xss_clean');
 $this->form_validation->set_rules('accept_terms','TOS','trim|required|xss_clean'); // Need to add custom error message 

if ( $this->form_validation->run() === TRUE ) {

}else{

}
?>

当用户没有选择TOS时,我必须说

  

请阅读并接受我们的条款和条件。

注意:我添加了form_error功能来显示个别错误

2 个答案:

答案 0 :(得分:9)

我会做这样的事情,

if ($this->form_validation->run() === TRUE ) {
   if(!$this->input->post('accept_terms')){
      echo "Please read and accept our terms and conditions.";
      // Redirect
   }
}
else{

}

对于自定义消息,您可以调用自定义验证函数,如

$this->form_validation->set_rules('accept_terms', '...', 'callback_accept_terms');

然后在控制器中设置此方法:

function accept_terms() {
    if (isset($_POST['accept_terms'])) return true;
    $this->form_validation->set_message('accept_terms', 'Please read and accept our terms and conditions.');
    return false;
}

答案 1 :(得分:0)

你可以把值= 1并检查codeigniter,如下所示:

&#13;
&#13;
<input type="checkbox" name="accept_terms" value="1" /> Accept TOS<br>
$this->form_validation->set_rules('accept_terms','TOS','trim|required|xss_clean|greater_than[0]');
&#13;
&#13;
&#13;