Question

我有几个阵列，我只会说四个。例如：

LOCATION  = [:new_york, :california, :alaska, :missouri, :mississippi, :florida]
TYPE      = [:high_rise, :mid_rise, :low_rise, :loft, :townhouse, :hotel]
OWNERSHIP = [:coop, :condo, :condop, :rental, :single_family, :multi_family]
BLDG_AGE  = [:historic, :pre-war, :post-war, :modern]

我需要一个生成这些组合的脚本。以下是一些例子：

:new_york
:new_york, :high_rise
:new_york, :high_rise, :coop
:new_york, :high_rise, :coop, :historic

这些是简单的，只是一堆嵌套循环。我还需要其他组合。例如：

:new_york, :coop
:new_york, :pre-war
:new_york, :rental, :modern
:new_york, :high_rise, :single_family

但是，只考虑每个组合，只有LOCATION的成员才能单独出现。

Answer 1

假设您想要:pre_war，:post_war而不是:pre-war，:post-war：

LOCATION  = [:new_york, :california, :alaska, :missouri, :mississippi, :florida]
TYPE      = [:high_rise, :mid_rise, :low_rise, :loft, :townhouse, :hotel]
OWNERSHIP = [:coop, :condo, :condop, :rental, :single_family, :multi_family]
BLDG_AGE  = [:historic, :pre_war, :post_war, :modern]

LOCATION.product([nil] + TYPE, [nil] + OWNERSHIP, [nil] + BLDG_AGE)
.map(&:compact)

或更浓缩：

LOCATION.product(*[TYPE, OWNERSHIP, BLDG_AGE].map{|a| [nil] + a})
.map(&:compact)

从几个哈希生成每个组合

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