Question

我正在尝试从数组中剪切ABCservice和DEFService并打印它们。我在这里缺少什么？

  urlArray=('http://server:port/ABCservice/services/ABCservice?wsdl' 'http://server:port/DEFservice/services/DEFservice?wsdl')   
        for url in "${urlArray[@]}"
         do
            service=echo $url|cut -f4 -d/
            echo $service
        done

预期输出：

ABCService
DEFService

当前输出：

./test1.sh: line 6: http://server:port/ABCservice/services/ABCservice?wsdl: No such file or directory
./test1.sh: line 6: http://server:port/DEFservice/services/DEFservice?wsdl: No such file or directory

Answer 1

这是什么？

service=$(echo $url | cut -d"/" -f4)
echo $service

或直接

echo $(echo $url | cut -d"/" -f4)

代码中的问题：

service=echo $url|cut -f4 -d\

要在变量中保存命令输出，我们这样做：service=$(command)。
您的cut已将\作为分隔符而不是/。最好用括号括起来：-d "/"

Answer 2

service=$(echo $url | cut -d/ -f6 | cut -d\? -f1)
echo $service

Answer 3

使用bash字符串函数：

for i in "${!urlArray[@]}"; do 
    urlArray[i]="${urlArray[i]%\?*}"
    urlArray[i]="${urlArray[i]##*/}"
    echo ${urlArray[i]}
done



$ urlArray=('http://server:port/ABCservice/services/ABCservice?wsdl' 'http://server:port/DEFservice/services/DEFservice?wsdl') 
$ for i in "${!urlArray[@]}"; do urlArray[i]="${urlArray[i]%\?*}"; urlArray[i]="${urlArray[i]##*/}";  echo ${urlArray[i]} ; done
ABCservice
DEFservice

Answer 4

您的分隔符应为正斜杠

echo 'http://server:port/ABCservice/services/ABCservice?wsdl' | cut -f 4 -d/

Answer 5

\是转义字符。请改为\\。

Shell脚本剪切命令

5 个答案: