Question

我正在编写一个脚本，它将从文件夹中获取用户列表，并将它们与/ home /中的文件夹列表进行比较，并输出与服务器上活动用户列表不匹配的任何文件夹。现在，我几乎把它放在我想要它的地方，但是我很难理解如何在数组中删除我想要过滤的内容列表，将其与$ COMPARE的输出进行比较然后只输出那些文件夹不匹配我想要过滤掉的东西。

到目前为止，这是我的代码：

# Script for finding and displaying home folders that don't currently belong to an active user on the server
HOMEOUT=$(mktemp)
USEROUT=$(mktemp)
USERS=( $(find /var/cpanel/users/ -maxdepth 1 -type f -printf '%P\n' | sort >$USEROUT) )
HOME=( $(find /home* -maxdepth 1 -type d -printf '%P\n' | grep -v '^$' | sort >$HOMEOUT) )
FILTER=( 'mysql' 'migrate-sslrigs' 'rvadmin' 'cpeasyapache' 'lost+found' 'cpanelbranding' 'installd'
    'cprestore' 'cprubybuild' 'cprubygemsbuild' 'MySQL-install' 'mysql_upgrade' 'securervsite' 'virtfs' 'zabbix' )


# Compare the two files and only output folders from /home/ which don't match the active_users list
COMPARE=`comm -23 $HOMEOUT $USEROUT`

我当时认为“案例”可能是去这里的方式，但我有问题搞清楚，我不确定这是否是解决这个问题的最佳方法。任何指导/协助都将不胜感激。

已更新

这是当前的代码：

HOMEOUT=$(mktemp)
USEROUT=$(mktemp)
USERS=( $(find /var/cpanel/users/ -maxdepth 1 -type f -printf '%P\n' | sort >$USEROUT) )
HOME=( $(find /home* -maxdepth 1 -type d -printf '%P\n' | grep -v '^$' | sort >$HOMEOUT) )
FILTER=( 'mysql' 'migrate-sslrigs' 'rvadmin' 'cpeasyapache' 'lost+found' 'cpanelbranding' 'installd'
        'cprestore' 'cprubybuild' 'cprubygemsbuild' 'MySQL-install' 'mysql_upgrade' 'securervsite' 'virtfs' 'zabbix' 'cpeasyapache'
        '.cpan' '.cpcpan' '.cpanm' )


# Compare the two files and only output folders from /home/ which don't match the active_users list
COMPARE=`comm -23 "$HOMEOUT" "$USEROUT" |
            comm -23 - <(
                for f in "${FILTER[@]}"; do
                    echo "$f"
                done)`

# Find the disk space of each folder
 pushd /home/ >/dev/null
for x in "$COMPARE"; do
        du -s $x | sort -n | cut -f 2-|xargs -i du -sh {}
done
  popd >/dev/null


# House cleaning
rm -f $HOMEOUT $USEROUT

当我使用bash -x运行脚本时，它会显示以下内容：

+ FILTER=('mysql' 'migrate-sslrigs' 'rvadmin' 'cpeasyapache' 'lost+found' 'cpanelbranding' 'installd' 'cprestore' 'cprubybuild' 'cprubygemsbuild' 'MySQL-install' 'mysql_upgrade' 'securervsite' 'virtfs' 'zabbix' 'cpeasyapache' '.cpan' '.cpcpan' '.cpanm')
++ comm -23 /tmp/tmp.fxYQB27380 /tmp/tmp.vwLWZ27381
++ comm -23 - /dev/fd/63
+++ for f in '"${FILTER[@]}"'
+++ echo mysql
+++ for f in '"${FILTER[@]}"'
+++ echo migrate-sslrigs
+++ for f in '"${FILTER[@]}"'
+++ echo rvadmin
+++ for f in '"${FILTER[@]}"'
+++ echo cpeasyapache
+++ for f in '"${FILTER[@]}"'
+++ echo lost+found
+++ for f in '"${FILTER[@]}"'
+++ echo cpanelbranding
+++ for f in '"${FILTER[@]}"'
+++ echo installd
+++ for f in '"${FILTER[@]}"'
+++ echo cprestore
+++ for f in '"${FILTER[@]}"'
+++ echo cprubybuild
+++ for f in '"${FILTER[@]}"'
+++ echo cprubygemsbuild
+++ for f in '"${FILTER[@]}"'
+++ echo MySQL-install
+++ for f in '"${FILTER[@]}"'
+++ echo mysql_upgrade
+++ for f in '"${FILTER[@]}"'
+++ echo securervsite
+++ for f in '"${FILTER[@]}"'
+++ echo virtfs
+++ for f in '"${FILTER[@]}"'
+++ echo zabbix
+++ for f in '"${FILTER[@]}"'
+++ echo cpeasyapache
+++ for f in '"${FILTER[@]}"'
+++ echo .cpan
+++ for f in '"${FILTER[@]}"'
+++ echo .cpcpan
+++ for f in '"${FILTER[@]}"'
+++ echo .cpanm

但是，输出仍会显示任何应该被过滤掉的所述文件夹。我觉得回声本身是不够的，实际上从输出中删除任何与$ FILTER匹配的内容可能会丢失。

思想？

Answer 1

您可以用以下内容替换最后一行：

COMPARE=`comm -23 "$HOMEOUT" "$USEROUT" |
            comm -23 - <(
                for f in "${FILTER[@]}"; do
                    echo "$f"
                done | sort)`

这部分：

<(for f in "${FILTER[@]}"; do
    echo "$f"
  done | sort)

被bash替换为管道读取端的文件名连接到<( )内的脚本输出，后者打印每行FILTER数组排序成员。

此命令：

comm -23 - <(
    for f in "${FILTER[@]}"; do
        echo "$f"
    done | sort)`

输出来自其输入的行，这些行不会出现在FILTER数组中。

将数组列表与bash中的结果进行比较

1 个答案: