我遇到了两个mysql
表的问题。我已经完成了一些代码,我认为我接近解决方案,但我不确定这是否正确。
所以这是两个表:
Table 1: Blogs
Columns: ID, agp_name, agp_url, agp_username, agp_password
Table 2: Keywords
Columns: ID, agp_user_id, agp_order_id, agp_blog_id, agp_keywords, agp_keywords_date
我想要的是根据以下条件从Table1中获取一个随机行:如果agp_keyword
与过去5天内的某个关键字匹配,则不包含在结果中。
到目前为止,我做到了这一点:
SELECT
t1.agp_user_id, t1.agp_order_id, t1.agp_blog_id, t1.agp_keywords, t1.agp_keywords_date, t2.agp_name, t2.agp_url, t2.agp_username, t2.agp_password
FROM table1 AS t1
INNER JOIN (
SELECT ID, agp_name, agp_url, agp_username, agp_password, agp_blogposts
FROM table2
) AS t2 ON t1.agp_blog_id = t2.ID
WHERE
t1.agp_keywords NOT LIKE "%keyword1%" AND
t1.agp_keywords NOT LIKE "%keyword2%" AND
t1.agp_keywords_date BETWEEN (1369440000 AND 1369932432)
ORDER BY RAND() LIMIT 1
但是这不能正常工作。任何帮助将不胜感激。
答案 0 :(得分:0)
试试这个,你的原始规格有点令人困惑:(
SELECT keywords.agp_user_id,
keywords.agp_order_id,
keywords.agp_blog_id,
keywords.agp_keywords,
keywords.agp_keywords_date,
blogs.agp_name,
blogs.agp_url,
blogs.agp_username,
blogs.agp_password
FROM blogs
LEFT JOIN keywords
ON keywords.agp_blog_id = blogs.ID
AND keywords.agp_keywords NOT LIKE "%keyword1%"
AND keywords.agp_keywords NOT LIKE "%keyword2%"
AND FROM_UNIXTIME(keywords.agp_keywords_date) > (DATE_SUB(CURDATE(), INTERVAL 5 DAYS))
ORDER BY RAND() LIMIT 1