我正试图审查WebSockets HTML5和JavaScript的工作原理。我没有看到任何错误,但似乎只是挂了一会儿,然后调用已关闭的回调。不知道我做错了什么,但我认为onopen回调函数在这里被调用。
var socket;
window.onload = function(argument) {
try
{
document.getElementById("console").innerHTML = "Opening WebSocket...";
socket = new WebSocket("ws://undergroundtechnetwork.com:8080/");
socket.onopen = function(){
document.getElementById("console").innerHTML += "<br />WebSocket opened.";
}
socket.onmessage = function(message){
document.getElementById("console").innerHTML += "<br />WebSocket recieved a message: " + message;
}
socket.onclose = function(){
document.getElementById("console").innerHTML += "<br />WebSocket status: " + GetSocketStateName(socket.readyState);
}
socket.onerror = function(e){
document.getElementById("console").innerHTML += "<br />WebSocket error message:<br />" + JSON.stringify(e);
}
}catch(e){
document.getElementById("console").innerHTML += "<br />Exception: " + e;
}
}
function GetSocketStateName(state){
var strSocketState;
if(socket.readyState == 0){
strSocketState = "Connecting";
}else if(socket.readyState == 1){
strSocketState = "Open";
}else if(socket.readyState == 2){
strSocketState = "Closing";
}else if(socket.readyState == 3){
strSocketState = "Closed";
}
return strSocketState;
}
更新
这是我在错误中遇到的错误。我没有得到8080的错误,但那是因为它不是真正的开放(它是托管服务服务器)
{ “cancelBubble”:假 “的returnValue”:真 “srcElement”:{ “binaryType”: “斑点”, “扩展”: “”, “协议”: “”, “bufferedAmount”:0,” readyState的 “:0,” URL “:” WS://undergroundtechnetwork.com/ “ ”URL“: ”WS://undergroundtechnetwork.com/“}, ”defaultPrevented“:假的, ”时间戳“:1369930726244,” 取消“:假,” 泡沫 “:假” 的EventPhase “:2”,currentTarget当前 “:{” binaryType “:” 斑点 “ ”扩展“: ”“, ”协议“: ”“, ”bufferedAmount“:0,” readyState的 “:0,” URL “:” WS://undergroundtechnetwork.com/ “ ”URL“: ”WS://undergroundtechnetwork.com/“}, ”目标“:{ ”binaryType“: ”斑点“,”扩展名 “:” “ ”协议“: ”“, ”bufferedAmount“:0 ”readyState的“:0, ”URL“: ”WS://undergroundtechnetwork.com/“, ”URL“:” WS:// undergroundtechnetwork的.com / “},” 类型 “:” 错误“}
答案 0 :(得分:1)
您的JavaScript似乎没问题。如果你改变了
socket = new WebSocket("ws://undergroundtechnetwork.com:8080/");
让我们说
socket = new WebSocket("ws://echo.websocket.org");
它工作正常。请尝试调整WebSocket服务器。