Question

我有一个结构如下的文件：

<?xml version="1.0" encoding="UTF-8"?>
<EventSchedule>
    <Event Uid="2" Type="Main Event">
        <IsFixed>True</IsFixed>
        <EventKind>MainEvent</EventKind>
        <Fields>
            <Parameter Name="Type" Value="TV_Show"/>
            <Parameter Name="Name" Value="The Muppets"/>
            <Parameter Name="Duration" Value="00:30:00"/>
        </Fields>
    </Event>
    <Event>
    ...and so on
    </Event>
</EventSchedule>

我不完全确定它是否是有效的XML，但我需要将其导入SQL Server，但我尝试的所有内容似乎都无法正常工作。

任何人都可以通过一些示例代码或建议使用哪种方法向我指出正确的方向？

理想情况下，我希望将原始数据放入平面表格中，如下所示：

Name        | Type    | Duration | EventKind

The Muppets | TV_Show | 00:30:00 | MainEvent

最后这是来自相当大的文件，我需要定期导入。

谢谢，pugu

Answer 1

试试这个：

DECLARE @XML XML = '<EventSchedule>
    <Event Uid="2" Type="Main Event">
        <IsFixed>True</IsFixed>
        <EventKind>MainEvent</EventKind>
        <Fields>
            <Parameter Name="Type" Value="TV_Show"/>
            <Parameter Name="Name" Value="The Muppets"/>
            <Parameter Name="Duration" Value="00:30:00"/>
        </Fields>
    </Event>
    <Event Uid="3" Type="Secondary Event">
        <IsFixed>True</IsFixed>
        <EventKind>SecondaryEvent</EventKind>
        <Fields>
            <Parameter Name="Type" Value="TV_Show"/>
            <Parameter Name="Name" Value="The Muppets II"/>
            <Parameter Name="Duration" Value="00:30:00"/>
        </Fields>
    </Event>
</EventSchedule>'

SELECT
    EventUID = Events.value('@Uid', 'int'),
    EventType = Events.value('@Type', 'varchar(20)'),
    EventIsFixed =Events.value('(IsFixed)[1]', 'varchar(20)'),
    EventKind =Events.value('(EventKind)[1]', 'varchar(20)')
FROM
 @XML.nodes('/EventSchedule/Event') AS XTbl(Events)

给我一个输出：

enter image description here

当然，你可以轻松地做一个

INSERT INTO dbo.YourTable(EventUID, EventType, EventIsFixed, EventKind)
   SELECT 
         ......

将该数据插入关系表。

更新：假设您的XML文件已经存在 - 您可以使用此代码将XML文件加载到SQL Server中的XML变量中：

DECLARE @XmlFile XML

SELECT @XmlFile = BulkColumn
FROM  OPENROWSET(BULK 'path-to-your-XML-file', SINGLE_BLOB) x;

然后使用上面的代码片段来解析XML。

更新＃2：如果您还需要参数 - 请使用此XQuery语句：

SELECT
    EventUID = Events.value('@Uid', 'int'),
    EventType = Events.value('@Type', 'varchar(20)'),
    EventIsFixed = Events.value('(IsFixed)[1]', 'varchar(20)'),
    EventKind = Events.value('(EventKind)[1]', 'varchar(20)'),
    ParameterType = Events.value('(Fields/Parameter[@Name="Type"]/@Value)[1]', 'varchar(20)'),
    ParameterName = Events.value('(Fields/Parameter[@Name="Name"]/@Value)[1]', 'varchar(20)'),
    ParameterDuration = Events.value('(Fields/Parameter[@Name="Duration"]/@Value)[1]', 'varchar(20)')
FROM
    @XML.nodes('/EventSchedule/Event') AS XTbl(Events)

结果：

enter image description here

Answer 2

您可以通过创建目标表，然后是将xml元素映射到表列的模式映射文件来实现。

你的看起来可能有点像这样：

create table event (
    Type nvarchar(50),
    Name nvarchar(50),
    Duration nvarchar(50))

和此：

<?xml version="1.0" ?>
<Schema xmlns="urn:schemas-microsoft-com:xml-data" 
        xmlns:dt="urn:schemas-microsoft-com:xml:datatypes"  
        xmlns:sql="urn:schemas-microsoft-com:xml-sql" > 

   <ElementType name="Type" dt:type="string" />
   <ElementType name="Name" dt:type="string" />
   <ElementType name="Duration" dt:type="string" />

   <ElementType name="EventSchedule" sql:is-constant="1">
      <element type="Event" />
   </ElementType>

   <ElementType name="Event" sql:relation="Event">
      <element type="Type" sql:field="Type" />
      <element type="Name" sql:field="Name" />
      <element type="Duration" sql:field="Duration" />
   </ElementType>
</Schema>

然后，您可以使用XML批量加载器将XML加载到表中。

http://support.microsoft.com/kb/316005

Answer 3

如果你需要在没有XML变量的情况下（来自表值函数中的字符串）

SELECT 
    --myTempTable.XmlCol.value('.', 'varchar(36)') AS val 
     myTempTable.XmlCol.query('./ID').value('.', 'varchar(36)') AS ID 
    ,myTempTable.XmlCol.query('./Name').value('.', 'nvarchar(MAX)') AS Name 
    ,myTempTable.XmlCol.query('./RFC').value('.', 'nvarchar(MAX)') AS RFC 
    ,myTempTable.XmlCol.query('./Text').value('.', 'nvarchar(MAX)') AS Text 
    ,myTempTable.XmlCol.query('./Desc').value('.', 'nvarchar(MAX)') AS Description 

    --,myTempTable.XmlCol.value('(Desc)[1]', 'nvarchar(MAX)') AS DescMeth2
FROM 
(
    SELECT  
        CAST('<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
        <data-set>
            <record>
                <ID>1</ID>
                <Name>A</Name>
                <RFC>RFC 1035[1]</RFC>
                <Text>Address record</Text>
                <Desc>Returns a 32-bit IPv4 address, most commonly used to map hostnames to an IP address of the host, but it is also used for DNSBLs, storing subnet masks in RFC 1101, etc.</Desc>
            </record>
            <record>
                <ID>2</ID>
                <Name>NS</Name>
                <RFC>RFC 1035[1]</RFC>
                <Text>Name server record</Text>
                <Desc>Delegates a DNS zone to use the given authoritative name servers</Desc>
            </record>
        </data-set>
        ' AS xml) AS RawXml
) AS b 
--CROSS APPLY b.RawXml.nodes('//record/ID') myTempTable(XmlCol);
CROSS APPLY b.RawXml.nodes('//record') myTempTable(XmlCol);

或者来自档案：

IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[tfu_RPT_SEL_XmlData]') AND type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
DROP FUNCTION [dbo].[tfu_RPT_SEL_XmlData]
GO



CREATE FUNCTION [dbo].[tfu_RPT_SEL_XmlData]
(
     @in_language varchar(10) 
    ,@in_reportingDate datetime 
)
RETURNS TABLE
AS
RETURN 
(   

    SELECT 
        --myTempTable.XmlCol.value('.', 'varchar(36)') AS val 
         myTempTable.XmlCol.query('./ID').value('.', 'varchar(36)') AS ID 
        ,myTempTable.XmlCol.query('./Name').value('.', 'nvarchar(MAX)') AS Name 
        ,myTempTable.XmlCol.query('./RFC').value('.', 'nvarchar(MAX)') AS RFC 
        ,myTempTable.XmlCol.query('./Text').value('.', 'nvarchar(MAX)') AS Text 
        ,myTempTable.XmlCol.query('./Desc').value('.', 'nvarchar(MAX)') AS Description 
    FROM 
    (
        SELECT CONVERT(XML, BulkColumn) AS RawXml 
        FROM OPENROWSET(BULK 'D:\username\Desktop\MyData.xml', SINGLE_BLOB) AS MandatoryRowSetName 
    ) AS b 
    CROSS APPLY b.RawXml.nodes('//record') myTempTable(XmlCol)

)


GO


SELECT * FROM tfu_RPT_SEL_XmlData('DE', CURRENT_TIMESTAMP);

e.g。

DECLARE @bla varchar(MAX)
SET @bla = 'BED40DFC-F468-46DD-8017-00EF2FA3E4A4,64B59FC5-3F4D-4B0E-9A48-01F3D4F220B0,A611A108-97CA-42F3-A2E1-057165339719,E72D95EA-578F-45FC-88E5-075F66FD726C'

-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT 
    x.XmlCol.value('.', 'varchar(36)') AS val 
FROM 
(
    SELECT 
    CAST('<e>' + REPLACE(@bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b 
CROSS APPLY b.RawXml.nodes('e') x(XmlCol);

所以你可以拥有像

这样的功能

SELECT * FROM MyTable 
WHERE UID IN 
(
    SELECT 
        x.XmlCol.value('.', 'varchar(36)') AS val 
    FROM 
    (
        SELECT 
        CAST('<e>' + REPLACE(@bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
    ) AS b 
    CROSS APPLY b.RawXml.nodes('e') x(XmlCol)
)

Answer 4

如果您尝试将XML导入为“纯”XML字段，则应创建一个这样的表（显然可以根据需要添加许多其他字段）：

CREATE TABLE [dbo].[TableXML](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [XmlContent] [xml] NOT NULL -- specify [xml] type
)

然后，您可以轻松地将XML作为字符串插入：

INSERT INTO [dbo].[TableXML]
           ([XmlContent])
     VALUES
           ('<?xml version="1.0" encoding="UTF-8"?>
               <EventSchedule>
                 <Event Uid="2" Type="Main Event">
                   <IsFixed>True</IsFixed>
                   <EventKind>MainEvent</EventKind>
                   <Fields>
                     <Parameter Name="Type" Value="TV_Show"/>
                     <Parameter Name="Name" Value="The Muppets"/>
                     <Parameter Name="Duration" Value="00:30:00"/>
                   </Fields>
                </Event>
              </EventSchedule>')

然后从MSDN t-SQL XML

开始查询

如果您希望将其存储为字符串，请使用varchar（max）代替[XML]列类型和相同的插入。但如果您想轻松查询，我建议[XML]类型。使用扁平字符串方法需要大量工作，除非您将实现一些应用程序代码来解析它并存储在平面表中。一个好的方法可能是“压缩”TABLE中的XML存储和使用扁平字段处置的数据检索的VIEW。

Answer 5

如何将以下XML数据加载到SQL中

<?xml version="1.0" encoding="utf-8"?> 
<DataTable xmlns="SmarttraceWS"> 
  <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> 
    <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:MainDataTable="ActivityRecords" msdata:UseCurrentLocale="true"> 
      <xs:complexType> 
        <xs:choice minOccurs="0" maxOccurs="unbounded"> 
          <xs:element name="ActivityRecords"> 
            <xs:complexType> 
              <xs:sequence> 
                <xs:element name="ReferenceID" type="xs:long" minOccurs="0" /> 
                <xs:element name="IMEI" type="xs:string" minOccurs="0" /> 
                <xs:element name="Asset" type="xs:string" minOccurs="0" /> 
                <xs:element name="Driver" type="xs:string" minOccurs="0" /> 
                <xs:element name="DateTime" type="xs:string" minOccurs="0" /> 

              </xs:sequence> 
            </xs:complexType> 
          </xs:element> 
        </xs:choice> 
      </xs:complexType> 
    </xs:element> 
  </xs:schema> 
  <diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1"> 
    <DocumentElement xmlns=""> 
      <ActivityRecords diffgr:id="ActivityRecords1" msdata:rowOrder="0"> 
        <ReferenceID>2620443016</ReferenceID> 
        <IMEI>013795001360346</IMEI> 
        <Asset>L-93745</Asset> 
        <Driver>N/A</Driver> 
        <DateTime>2019-10-14 12:00:35</DateTime> 

              </ActivityRecords> 
    </DocumentElement> 
  </diffgr:diffgram> 
</DataTable>

导入＆＃39; xml＆＃39;进入Sql Server

5 个答案: