使用Cursor将值添加到现有表

时间:2013-05-30 07:42:46

标签: sql sql-server cursor

通过运行此代码可以正常工作,但是当我向表中添加更多值时,它就不再起作用了。感谢您的帮助,谢谢。

此代码完美无缺:

declare @id int
declare @empid int
set @id = 0
declare @schedindate datetime
declare @ss nvarchar(100)
declare @indice nvarchar(2)
declare @FromDate datetime
declare @ToDate datetime
declare @TimeInR datetime
declare @TimeOutR datetime
declare @departmentID int 
declare @PositionID int
declare @BranchID int
declare @SupervisorID int
declare @GradeID int
declare @Custom1ID int
declare @Custom2ID int
declare @PayClassID int
declare @EmploymentType int
set @FromDate = '2009-01-14'
set @ToDate = '2010-01-30'
delete from table1
declare cc cursor for select distinct empid from ta_timecard where schedindate between @FromDate and @ToDate
open cc
fetch next from cc into @empid
while (@@fetch_status = 0)
begin
    set @id = @id + 1
    insert into table1 (ID, EmpID) values (@id, @empid)

    declare cc2 cursor for select distinct departmentid from ta_timecard where empid = @empid and schedindate between @FromDate and @ToDate
    open cc2
    fetch next from cc2 into @departmentID

    while (@@fetch_status = 0)
    begin
        set @indice = cast(datediff(day, @fromdate, @schedindate) as nvarchar(4))
        set @ss = 'update table1 set departmetid = ' + convert(nvarchar(4), @departmentID)
            + ' where empid = ' + convert(nvarchar(4), @empid)

        execute sp_executesql @ss
        fetch next from cc2 into @departmentID
    end
    close cc2
    deallocate cc2
fetch next from cc into @empid
end
close cc
Deallocate cc
GO

enter image description here

但是当我向表中添加更多值时,我得到的第一行只受影响

enter image description here

declare @id int
declare @empid int
set @id = 0
declare @schedindate datetime
declare @ss nvarchar(100)
declare @indice nvarchar(2)
declare @FromDate datetime
declare @ToDate datetime
declare @TimeInR datetime
declare @TimeOutR datetime
declare @departmentID int 
declare @PositionID int
declare @BranchID int
declare @SupervisorID int
declare @GradeID int
declare @Custom1ID int
declare @Custom2ID int
declare @PayClassID int
declare @EmploymentType int
set @FromDate = '2009-01-14'
set @ToDate = '2010-01-30'
delete from table1
declare cc cursor for select distinct empid from ta_timecard where schedindate between @FromDate and @ToDate
open cc
fetch next from cc into @empid
while (@@fetch_status = 0)
begin
    set @id = @id + 1
    insert into table1 (ID, EmpID) values (@id, @empid)

    declare cc2 cursor for select distinct departmentid, branchid from ta_timecard where empid = @empid --and schedindate between @FromDate and @ToDate
    open cc2
    fetch next from cc2 into @departmentID, @BranchID--,@PositionID

    while (@@fetch_status = 0)
    begin
        set @indice = cast(datediff(day, @fromdate, @schedindate) as nvarchar(4))
        set @ss = 'update table1 set departmetid = ' + convert(nvarchar(4), @departmentID) 
            +', branchid = ' + convert(nvarchar(4), @BranchID) 
            --+ ', positionid = ' + convert(nvarchar(4), @PositionID)
            + ' where empid = ' + convert(nvarchar(4), @empid)
print(@ss)
        execute sp_executesql @ss
        fetch next from cc2 into @departmentID, @BranchID--, @PositionID
    end
    close cc2
    deallocate cc2
fetch next from cc into @empid
end
close cc
Deallocate cc
GO

编辑: 这是表ta_TimeCard

enter image description here

2 个答案:

答案 0 :(得分:1)

你需要在NULL值上检查@BranchID

+ ISNULL(', branchid = ' + convert(nvarchar(4), @BranchID), '')

答案 1 :(得分:0)

请从

更改您的查询
  set @ss = 'update table1 set departmetid = '

set @ss = 'update table1 set departmentid = '

n可能会影响您的结果