我正在尝试在使用AsyncTask<URL, Integer, Long>
扩展的initial_background类中显示Toast。我在logcat中收到此错误。
public class InitialBackgroundTask extends AsyncTask<URL, Integer, Long> {
@Override
protected Long doInBackground(URL... params) {
// TODO Auto-generated method stub
show a = new show();
a.loop();
return null;
}
public class show {
void loop()
{
for(int i=0; i<10; i++)
{
Toast.makeText(MainActivity.me, "test", Toast.LENGTH_LONG).show();
}
}
}
这是一个例外:
05-30 12:08:12.641: E/AndroidRuntime(30840): FATAL EXCEPTION: AsyncTask #1
05-30 12:08:12.641: E/AndroidRuntime(30840): java.lang.RuntimeException: An error occured while executing doInBackground()
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.os.AsyncTask$3.done(AsyncTask.java:278)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.FutureTask.setException(FutureTask.java:124)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.FutureTask.run(FutureTask.java:137)
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:208)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.lang.Thread.run(Thread.java:856)
05-30 12:08:12.641: E/AndroidRuntime(30840): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.os.Handler.<init>(Handler.java:121)
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.widget.Toast$TN.<init>(Toast.java:317)
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.widget.Toast.<init>(Toast.java:91)
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.widget.Toast.makeText(Toast.java:233)
05-30 12:08:12.641: E/AndroidRuntime(30840): at com.example.toast.show.loop(show.java:11)
05-30 12:08:12.641: E/AndroidRuntime(30840): at com.example.toast.InitialBackgroundTask.doInBackground(InitialBackgroundTask.java:13)
05-30 12:08:12.641: E/AndroidRuntime(30840): at com.example.toast.InitialBackgroundTask.doInBackground(InitialBackgroundTask.java:1)
05-30 12:08:12.641: E/AndroidRuntime(30840): at android.os.AsyncTask$2.call(AsyncTask.java:264)
05-30 12:08:12.641: E/AndroidRuntime(30840): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
05-30 12:08:12.641: E/AndroidRuntime(30840): ... 5 more
以上代码展示了整个故事。实际上,我想在doInBackground方法中显示吐司
答案 0 :(得分:27)
您无法在后台线程上更新UI。在后台线程上调用doInBackground()
。您应该在UI线程上更新UI。
runOnUiThread(new Runnable(){
@Override
public void run(){
//update ui here
// display toast here
}
});
在UI线程上调用 onPreExecute()
,onPostExecute(Result)
。所以你可以在这里展示吐司。
onProgressUpdate(Progress...)
后在UI线程上调用的 publishProgress(Progress...)
可用于为进度条设置动画或在文本字段中显示日志。
doInBackground()
计算的结果是onPostExecute(Result)
的参数,因此请在doinBackground()
中返回结果并在onPostExecute(Result)
您也可以使用@Stine Pike建议的处理程序
为清楚起见,请查看以下主题下的链接: 4个步骤。
http://developer.android.com/reference/android/os/AsyncTask.html
答案 1 :(得分:22)
创建一个处理程序对象并使用它执行所有Toast消息。
@Override
protected Void doInBackground(Void... params) {
Handler handler = new Handler(context.getMainLooper());
handler.post( new Runnable(){
public void run(){
Toast.makeText(context, "Created a server socket",Toast.LENGTH_LONG).show();
}
});
}
答案 2 :(得分:4)
这是另一种方法,这里没有提到如下:
第1步:将处理程序定义为全局
Handler handler;
第2步:在 doInBackground()方法中初始化处理程序,如下所示:
@Override
protected Void doInBackground(Void... params) {
Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
if (msg.what == 1) {
//your code
}
}
};
}
第3步: 现在,您可以通过调用
在代码中的任何位置调用该处理程序if(handler != null){
handler.sendEmptyMessage(1);
}
您可以做的更多事情是您可以通过处理程序发送数据,如下所示:
Message message = new Message();
Bundle bundle = new Bundle();
bundle.putInt("KEY", value);
message.setData(bundle);
handler.sendMessage(message);
并处理您在处理程序中的数据,如下所示
handler = new Handler(){
@Override
public void handleMessage(Message message) {
Bundle bundle = message.getData();
Integer value = bundle.getInt("KEY");
}
};
答案 3 :(得分:2)
在onPostExecute或onPreExecute中显示你的Toast。 doInBackGround在一个单独的线程上运行,但另外两个方法在UI线程上运行。
但如果必须在doInBackGround中显示吐司,那么您可以使用Handler.post或runonUiThread来执行吐司。
答案 4 :(得分:2)
您无法在非UI线程中显示Toast(即在后台执行)。您可以尝试使用标记概念。
public class HttpRequest extends AsyncTask<String[], Void, String> {
boolean flag=false;
....
...
....
@Override
protected String doInBackground(String[]... params) {
//set flag as true when you need to trigger the Toast
try{
//Some Network Calls
} catch (HttpHostConnectException e) {
flag=true;
//Triggered Flas when i got Exceptions
}
}
@Override
protected void onPostExecute(String result) {
if(flag){
Toast.makeText(activity, "HttpHostConnectException Occured ", Toast.LENGTH_SHORT).show();
}
}
快乐编码.. !!!在这里输入代码
答案 5 :(得分:0)
你试图在非ui线程中显示toast,这就是为什么会出现这个错误。
如果你想在doInBackground方法中显示toast,那么你必须在UI线程中编写Toast逻辑
看看下面的回答链接 https://stackoverflow.com/a/11797945/582571
但不建议在非ui线程下进行UI操作
答案 6 :(得分:0)
我们可以通过将接口传递给AsyncTask类并在 onPostExecute 方法中进行回调来实现。
public interface IResult {
void onSuccess(String result);
void onError(String error);
}
public static class AsyncTaskClass extends AsyncTask<String, String, Boolean> {
IResult iResult;
AsyncTaskClass(IResult iResult){
this.iResult = iResult;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected Boolean doInBackground(String... params) {
boolean result;
try {
//doing BackGround Operation Here
result = true;
} catch (Exception e) {
Log.e(TAG,"Error: " + e.getMessage());
result = false;
}
return result;
}
@Override
protected void onPostExecute(Boolean success) {
super.onPostExecute(success);
Log.w(TAG, "On Post Execute: " + success);
if(success)
iResult.onSuccess("AsyncTask done successfully.");
else
iResult.onSuccess("Sorry! something went wrong.");
}
}
IResult iResult = new IResult() {
@Override
public void onSuccess(String result) {
Toast.makeText(PostActivity.this, result, Toast.LENGTH_LONG).show();
}
@Override
public void onError(String error) {
Toast.makeText(PostActivity.this, error, Toast.LENGTH_LONG).show();
}
};
String param1 = "some value 1";
String param2 = "some value 2";
new AsyncTaskClass(iResult).execute(param1, param2);`
答案 7 :(得分:0)
使用SDK 29
public class LoginControl extends AsyncTask<String, Void, String> {
private final Context context;
public LoginControl (Context context) {
this.context = context;
}
@Override
protected String doInBackground(String... strings) {
//do something
}
@Override
protected void onPostExecute(TokenBean tokenBean) {
Toast.makeText(context, "hello Toast", Toast.LENGTH_SHORT).show();
}
}
在MainActivity.class
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
String url="something";
Context context = getApplicationContext();
new LoginControl(context).execute(url);
}